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3 years ago

Help me please ASAP!!!!

Mathematics

2 answers:

Alex3 years ago

4 0

ummmmmm you dont need the explanation and I'd rather not type but trust me its d, good luck!

RoseWind [281]3 years ago

3 0

Answer:

Step-by-step explanation:

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protocol for flushing a cooling water system at a nuclear reactor requires that a drain valve be opened while the fill pumps are

Lyrx [107]

Answer:

Step-by-step explanation:

drain empties 1/10 of the desired amount per minute

pump fills 1/14 of the desired amount per minute

when both are active, the net drain is 1/10-1/14 = 1/35 of the desired amount per minute

It takes 35 minutes to reach the cut-off level.

3 0

3 years ago

Solve the following inequality: –1 > –2(x – 4) – 5(4x – 7).

NikAS [45]

-1 > -2(x-4) - 5(4x - 7)
-1 > -2x + 8 - 20x + 35
-1 > -22x + 43
-1 - 43 > - 22x
-44 > - 22x
-44/-22 < x
2 < x....or x > 2

6 0

3 years ago

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago

Help me its due in a little

soldi70 [24.7K]

Answer:

a-50 b-300

Step-by-step explanation:

3 0

3 years ago

Which system of equations would have no solution? pls helpp

Leya [2.2K]

Answer:

3x+y=8 and 3x+y=9

Step-by-step explanation:

Assume these two equations:

a1x+b1y+c1=0

a2x+b2y+c2=0

If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.

In these case, take a look at the last option:

$3x + y = 8 \\ 3x + y = 9$

Re-write 'em as a standard form:

$3x + y - 8 = 0 \\ 3x + y - 9 = 0$

So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:

$\frac{3}{3} = \frac{1}{1} ≠ \frac{ - 8}{ - 9}$

And they do not have any collision point

6 0

2 years ago

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