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marusya05 [52]
3 years ago
8

The Area of a rectangular patio is 5 5/8 square yards,and it's length is 1 1/2 yards.What is the patio's width,in yards?

Mathematics
1 answer:
fgiga [73]3 years ago
8 0
Take both mixed numbers (a whole number plus a fraction) and turn them into improper fractions ( a numerator (top number) bigger than the denominator (bottom number). To do this, multiply the denominator by the whole number, and add the result to the numerator.
5 5/8 will become 45/8
1 1/2 will become 3/2.
Area is length* width, so width would be Area/ length. So 45/8 is the area and 3/2 is the length. Now you have (45/8)/(3/2). To divide fractions, take the second fraction and flip the numerator and denominator, forming the reciprocal (2/3). Now multiply 45/8 and 2/3
The result is 90/24, and simplifying would get 15/4, or 3 3/4. This is the width(or length)
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6 0
3 years ago
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Hello!

To solve algebraic equation, we will need to use the acronym SADMEP.

SADMEP is similar to PEMDAS, but it is strictly used for solving algebraic equations. Expanded, it is subtract, addition, division, multiplication, exponents, and then parentheses.

Looking at SADMEP, we see that subtract/addition comes first, then division/multiplication, and then exponents/parentheses.

In our equation, our goal is to isolate the variable, "x". Since we have two constants, -3 and 11, and -3 is on the side with the variable, we can add -3 to both sides of the equation first.

Therefore, the first operation needed to solve the equation is addition.

7 0
3 years ago
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