Volume of a cone = (1/3) pi x r^2 x h
Volume of a cylinder = pi x r^2 x h
Volume of the cylinder = pi x 2^2 x 3 = 37.68 cubic inches
Now set the volume for the cone to the volume of the cylinder and solve for the height.
37.68 = (1/3) x pi x r^2 x h
37.68 = (1/3) x pi x 3^2 x h
37.68 = (1/3) x pi x 9 x h
37.68 = 9.42 x h
h = 37.68 / 9.42
h = 4
The height of the cone is 4 cm.
Assign the following variables for the origina3l rectangle:
let w = width let w + 8 = length and the area would be w(w + 8) = w² + 8w
No for the second rectangle:
let (w + 4) = width and (w + 8 - 5) or (w + 3) = length
Area = length x width or (w + 4)(w + 3) = w² + 3w + 4w + 12 using the foil method to multiply to binomials. Simplified Area = w² + 7w + 12
Now our problem says that the two area will be equal to each other, which sets up the following equation:
w² + 8w = w² + 7w + 12 subtract w² from both sides
8w = 7w + 12 subtract 7w from both sides
w = 12 this is the width of our original rectangle
recall w + 8 = length, so length of the original rectangle would be 20
6+6
8+4
9+3
10+2
11+1
Hope this helps!
Which Statements?
You didn't put any Statements there
To draw the possible box make sure to follow the conditions required and organize the information.
<h3>What is a double box?</h3>
This is a type of chart that displays the data obtained by comparing two categories or elements. In this case, the goals of two different teams.
<h3>How to complete this task?</h3>
Read the prompt carefully.
Identify any conditions. For example, in this case, the number of goals obtained by the team warriors should be higher.
Organize the information in a chart.
Learn more about hockey in: brainly.com/question/3521414