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Alex
3 years ago
6

A student brings a bag of candy to share with the class. The bag of candy can be equally split among 4, 5, or 6 students with ea

ch receiving the same number of candies. Which of the following represents the smallest possible number of candies in the bag?
Select one:
A. 6
B. 30
C. 60
D. 90
E. 120
Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0
Its C. 60
60/4= 15
60/5= 12
60/6= 10
Temka [501]3 years ago
6 0

Answer: C. 60

Step-by-step explanation:

In this situation, they are asking  the least common multiple of 4,5, and 6.

Find the LCM of the numbers or the multiples of the numbers.

Multiples of 4 are  4, 8, 12,16, 20, 24,28,32,36, 40, 44,48,52,56,60.

Multiples of 5 are  5, 10,15,20,25,30,35,40,45,50,55,60.

Multiples of 6 are  6,12,18,24,30,36, 42, 48, 54, 60,

As we can see in their multiples, they do not share the multiple 6 or 30 .

But they all share the number 60 which means that 60  is the least possilbe number of candies in the bag.

Note that is can go on to be 90 or 120 but they are not the smallest ones.

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Can someone help me with this please ?
Arturiano [62]
3. (x + 1)/4 = 3 / 6
x + 1 = 3/6 x 4 = 2
x = 1

Scale factor = 6 / 4 = 1.5

Ratio of perimeters = 2 : 3

4. x / 21 = 20 / 15
x = 20 / 15 x 21 = 28

Scale factor = 20 / 15 = 4/3

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3 0
3 years ago
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Allushta [10]
A little Algebra, and we're home free!

We are given R = 20 and r2 = 75. We need to find r1.

The formula is 1/R = 1/r1 + 1/r2. Plug-in:
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r1 = 1/0.03666
r1 = 27.272

Our answer is r1 = 27 ohms.
6 0
3 years ago
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vekshin1

Answer:

The first one

Step-by-step explanation:

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5 0
2 years ago
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5 0
3 years ago
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