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Alex
3 years ago
6

A student brings a bag of candy to share with the class. The bag of candy can be equally split among 4, 5, or 6 students with ea

ch receiving the same number of candies. Which of the following represents the smallest possible number of candies in the bag?
Select one:
A. 6
B. 30
C. 60
D. 90
E. 120
Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0
Its C. 60
60/4= 15
60/5= 12
60/6= 10
Temka [501]3 years ago
6 0

Answer: C. 60

Step-by-step explanation:

In this situation, they are asking  the least common multiple of 4,5, and 6.

Find the LCM of the numbers or the multiples of the numbers.

Multiples of 4 are  4, 8, 12,16, 20, 24,28,32,36, 40, 44,48,52,56,60.

Multiples of 5 are  5, 10,15,20,25,30,35,40,45,50,55,60.

Multiples of 6 are  6,12,18,24,30,36, 42, 48, 54, 60,

As we can see in their multiples, they do not share the multiple 6 or 30 .

But they all share the number 60 which means that 60  is the least possilbe number of candies in the bag.

Note that is can go on to be 90 or 120 but they are not the smallest ones.

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The distribution of prices for home sales in a certain New Jersey county is skewed to the right with a mean of $290,000 and a st
I am Lyosha [343]

Answer:

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the mean of the Population( )= $290,000

Standard deviation of the Population = $145,000

Given the size of the sample 'n' = 100

Given 'X⁻'  be a random variable in Normal distribution

Let   X⁻ = 325,000

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }  = \frac{325000-290000}{\frac{145000}{\sqrt{100} } }  = 2.413

<u><em>Step(ii):</em></u>-

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413)

                           = 0.5 - A(2.413)

                           = 0.5 - 0.4920

                           = 0.008

<u><em>Final answer:-</em></u>

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

6 0
3 years ago
The sum of a number and 3 divided by 9
polet [3.4K]

Answer:

\frac{(x+3)}{9}

Step-by-step explanation:

6 0
3 years ago
Calculate the approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children.
mixas84 [53]

Answer:

The approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children is

0.01 or 1%.

Step-by-step explanation:

Number of selected children = 200

The probability of no child been diagnosed with ASD = P(None) = 198/200 = 0.99

Therefore, the probability of at least two children been diagnosed with ASD = 1 - 0.99 = 0.01.

This is the same as:

If 2 children have been diagnosed with ASD,

therefore, the approximate probability that at least 2 children have been diagnosed is:

2/200 = 0.01.  This value is equal to 1%.

The above are summed up in:

The probability of at least one = 1/200 = 0.05

Therefore, the probability of at least two = 0.05 * 2 = 0.01

b) Generally, to find the probability of at least one event happening, we calculate the probability of none and then subtract that result from 1. That is, P(at least one) = 1 – P(none).  For two events happening, the sum of the probability of at least one in two places is deducted from 1 to get the probability of at least two.

4 0
3 years ago
In a trivia game your team has -6 points. The other team has 15 points. What is the difference in points between the two teams
Alex

15 - -6 = 21. 21 points!

4 0
3 years ago
Read 2 more answers
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koban [17]

Answer:

(4,-2)

Step-by-step explanation:

plug in and simplify;

y+2=-3(x-4)

-2+2=-3(x-4)

0=-3x+12

3x=12

x=4

7 0
3 years ago
Read 2 more answers
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