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Alex
3 years ago
6

A student brings a bag of candy to share with the class. The bag of candy can be equally split among 4, 5, or 6 students with ea

ch receiving the same number of candies. Which of the following represents the smallest possible number of candies in the bag?
Select one:
A. 6
B. 30
C. 60
D. 90
E. 120
Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0
Its C. 60
60/4= 15
60/5= 12
60/6= 10
Temka [501]3 years ago
6 0

Answer: C. 60

Step-by-step explanation:

In this situation, they are asking  the least common multiple of 4,5, and 6.

Find the LCM of the numbers or the multiples of the numbers.

Multiples of 4 are  4, 8, 12,16, 20, 24,28,32,36, 40, 44,48,52,56,60.

Multiples of 5 are  5, 10,15,20,25,30,35,40,45,50,55,60.

Multiples of 6 are  6,12,18,24,30,36, 42, 48, 54, 60,

As we can see in their multiples, they do not share the multiple 6 or 30 .

But they all share the number 60 which means that 60  is the least possilbe number of candies in the bag.

Note that is can go on to be 90 or 120 but they are not the smallest ones.

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Please help me with this​
levacccp [35]

Answer:

They weigh 1/6

Step-by-step explanation:

So what you do is Divide 1/4 bye 1 1/2 so that you can figure out how much 1 1/2 bags weigh and that equals 1/6

8 0
3 years ago
What is the result when the number 64 is decreased by 4.1%? Round your answer to the nearest tenth.
Strike441 [17]

Answer:

61.4

Step-by-step explanation:

64 minus 4.1 percent is 61.376. Rounded to the nearest tenth would be 61.4.

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2 years ago
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What is the length of 2x+6
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Answer:   3 i hope this is right

Step-by-step explanation:

8 0
3 years ago
What is this answer I don't understand how to figure it out
Diano4ka-milaya [45]
These are congruent angles. So they would be equal to each other. 6x=4x+50

2x=50

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8 0
3 years ago
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On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe
Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let <em>X</em> denote delivery time of the mail delivered by Alice and <em>Y</em> denote delivery time of the mail delivered by Bob.

It i provided that:

X\sim U(9, 11)\\Y\sim U(10, 12)

The probability that Alice delivers the mail is, <em>p</em> = 1/4.

The probability that Bob delivers the mail is, <em>q</em> = 3/4.

The probability density function of a Uniform distribution with parameters [<em>a</em>, <em>b</em>] is:

f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Alice is:

f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Bob is:

f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50

Thus, the value of fₓ (10.5) is 0.50.

5 0
3 years ago
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