Q is located at (-5,2) Q" is located at (6,2) they bot h have the same Y value (2) so we know it was only a reflection across the X axis we need to find out where on the X axis it was reflected. the distance between -5 and 6 = 11 units 11/2 = 5.5 the reflection line was 5.5 units to the right of the original Q so the reflection line would be X = 0.5
