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3 years ago

Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. How many gallons can Joe's tank hold?

Mathematics

1 answer:

Korolek [52]3 years ago

3 0

Answer:

Amount of gas that can be hold by Joe's tank = 16 gallons.

Step-by-step explanation:

Given that Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. Now we need to find about how many gallons can Joe's tank hold.

So let's find change that happened after filling the gas.

Change = (5/8 full) - (1/4 full)

Change = (5/8 - 1/4) full

Change = (5/8 - 2/8) full

Change = (5 - 2)/8 full

Change = 3/8 full

So that means 3/8 full happens in 6 gallons

then 1 full will happen in 6/(3/8) gallons = 6*(8/3) gallons = 48/3 gallons = 16 gallons

So the amount of gas that can be hold by Joe's tank = 16 gallons.

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At 1 p.m., the number of cars in a parking lot is 78. Given the formula found in the first part of the question, An=78⋅1.09n, es

Harrizon [31]

Answer:

At 6 p.m., the number of cars in a parking lot is 120

Step-by-step explanation:

At 1 p.m., the number of cars in a parking lot is 78.

Given,

$A_n=78\cdot 1.09^n$

Note that

$A_0=78\cdot 1.09^0=78\cdot 1=78$

So, 1 p.m. goes for n = 0, then

6 p.m. goes for n = 5

Thus,

$A_5=78\cdot 1.09^5\approx 120$

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3 years ago

A phone costs $50 and goes on sale for 20% off. Select the amount that was discounted as well as the final price after the sale.

Afina-wow [57]

Answer:

40% because every 10$ = 20%

Step-by-step explanation:

6 0

3 years ago

Answer and show the work please?

dem82 [27]

(-5/8)(X) = -0.4
(-5/8)(X) = -4/10
X = (-4/10) / (-5/8)
X = (4/10) / (5/8)
X = (4/10)(8/5)
X = (2/5)(8/5)
X = 16/25

Letter D

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3 years ago

100 is the regular price if you buy one and get the other half price. Explain how this different from getting a 50% discount?

Vinvika [58]

100 = x + x/2

3x/2 = 100

x = 200/3

if there was 50% discount:

buying 1 would be $33.33

buying 2 would be $66.67

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3 years ago

The Fahrenheit and Celsius scales are related by the equation F=9/5C+32. What temperature is equal to a body temperature of 98.6

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$\textbf{Substitute\ in\ the\ equation}$

$\displaystyle 98.6 = \frac{9C}{5} +32$

$\textbf{Solve\ for\ }C$

$\displaystyle 66.6 = \frac{9C}{5}$

$333=9C$

$\large C=\textbf{37 \textdegree C}$

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2 years ago