Use the points (1997, 13) and (2005, 22) to write the slope intercept form of an equation for the line of fit shown in the scatt
er plot. Round values to the nearest hundredth.
A. y=0.89x+1985.44
B. y=1.13x-2243.65
C. y=1.13x-2233.63
D. y=0.89x-1985.44
A. y=0.89x+1985.44
B. y=1.13x-2243.65
C. y=1.13x-2233.63
D. y=0.89x-1985.44
1 answer:
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Using the z-distribution, we have that:
a) A sample of 601 is needed.
b) A sample of 93 is needed.
c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which z is the z-score that has a p-value of .
The margin of error is:
95% confidence level, hence, z is the value of Z that has a p-value of
, so
.
For this problem, we consider that we want it to be within 4%.
Item a:
- The sample size is <u>n for which M = 0.04.</u>
- There is no estimate, hence
Rounding up:
A sample of 601 is needed.
Item b:
The estimate is , hence:
Rounding up:
A sample of 93 is needed.
Item c:
The closer the estimate is to , the larger the sample size needed, hence, the correct option is A.
For more on the z-distribution, you can check brainly.com/question/25404151