Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)
Answer:8
Step-by-step explanation:
Answer : $ 9, 152
Luna invested $8000 for 36 months at an interest rate of 4.8%
Let P = principal
T = time
r = rate
Using the simple interest,
The total balance = Interest + principal
Balance = 1, 152 + 8000
Balance =$9, 152
The total money she will have at the end of the investment is $9, 152
Answer:
GH = 49
GJ = 35
HJ = 35
Step-by-step explanation:
:::::
Answer:
The slope is 2.2
Step-by-step explanation:
Since the point goes through (0,0) the slope is given by
m =y/x
4.4 / 2
2.2
