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tester [92]
3 years ago
8

LOOK AT PICTURE,THEN ANWSER QUESTION, WHOEVER ANSWERS CORRECT I WILL MARK BRAINIEST!!

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0
Answer:
B. 4/11

Solution:
Gradient=(y1-y2)/(x1-x2)
Gradient=(6-2)/(4-(-7)) =4/11
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25.
Setler79 [48]

Easy question

x=10

mECH=40

mHCD=50

mGCF=40

mECG=140

mGCD=13

<em><u>Hence</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>found</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>solution</u></em><em><u>.</u></em>

5 0
3 years ago
when a trend is drawn on the scatterplot there are 4 points above the trend line. about how many points should be below the tren
3241004551 [841]

Answer:

About 4 should be below

Step-by-step explanation:

4 0
4 years ago
A line has a slope of 1and passes through the point
Jobisdone [24]

\huge\boxed{y=x-3}

Start with point-slope form, where m is the slope and (x_1, y_1) is a known point on the line.

y-y_1=m(x-x_1)

Substitute in the known values.

y-3=1(x-6)

Distribute the 1 to the (x-6).

y-3=x-6

Add 3 to both sides.

\boxed{y=x-3}

7 0
4 years ago
Read 2 more answers
NEED ASAP<br><br> 1. Find the distance between (3√3, √11) and (−5√3, 5√11)
VLD [36.1K]

Answer:\sqrt20

Step-by-step explanation

7 0
3 years ago
Simplify (write without the absolute value sign): 120+x, if x &lt;- 120
Tju [1.3M]

Answer:

Step-by-step explanation:

hello :

120+x, if x <- 120

given : x <- 120    add 120      x+120<- 120+120

x+120< 0

8 0
3 years ago
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