LOOK AT PICTURE,THEN ANWSER QUESTION, WHOEVER ANSWERS CORRECT I WILL MARK BRAINIEST!!
1 answer:
You might be interested in
a) 70.1 m
The ball is moving by uniformly accelerated motion, with constant acceleration (acceleration due to gravity) towards the ground. The height of the ball at time t is given by the equation
where is the height of the ball at time t=0. Substituting t=1 s, we can find the height of the ball 1 seconds after it has been dropped:
b) 3.9 s
We can still use the same equation we used in the previous part of the problem:
This time, we want to find the time t at which the ball hits the ground, which means the time t at which h(t)=0. So we have
And solving for t we find
Answer:
4.71
Step-by-step explanation:
The radius of the circle is 3 and the angle of the sector is 60°.
The area of a sector is given as:
where α = central angle of sector
r = radius of circle
Hence, the area of the sector is:
The area of the sector is 4.71