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Mathematics

1 answer:

Gnom [1K]2 years ago

3 0

Answer:
B. 4/11

Solution:
Gradient=(y1-y2)/(x1-x2)
Gradient=(6-2)/(4-(-7)) =4/11

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Solve the equation -15=a/5 A=-3 A=-20 A=-10 A=-75

agasfer [191]

To solve any equation, you do whatever you need to do
to wind up with the unknown quantity all alone on one side.
BUT ... whatever you do to one side of the equation, you must
also do to the other side.

Here, we have the
he original equation: -15 = a/5

Multiply each side by 5 : -75 = a

and bada-bing, THERE's the solution !

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2 years ago

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

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3 years ago

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Find an equivalent ratio in simplest terms: 22 : 56

cupoosta [38]

Answer: 11:23

Step-by-step explanation: because that is the simplest terms