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Shalnov [3]
3 years ago
9

Create a word problem that can be represented by the expression below. Then, represent each product or quotient as a single rati

onal number. 8 times (-0.25), and -6 divide by (1 1/2) plz I will give you 100 points
Mathematics
1 answer:
Ber [7]3 years ago
6 0
I have eight coupons that are all worth -.25
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Helppppppp pllzzzzzzz
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I can't answer this because I don't know what she was starting with
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Which of the following is a “DON’T” regarding scannable résumés? a. Print on white paper with black ink b. Use special character
Masteriza [31]

Answer:

b.

Use special characters like italics and underlining

Step-by-step explanation:

i took the test

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3 years ago
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Use the formula for the area of a rectangle, A = lw, where A represents the area, l represents the length, and w represents the
IgorLugansk [536]

Answer:

Area = length × breadths

5 0
3 years ago
14)<br> Q<br> 28<br> ?<br> A) 112°<br> C) 50°<br> B) 65°<br> D) 125°<br> ASAP IM TAKING MY FINAL
lapo4ka [179]

Answer:

112

Step-by-step explanation:

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5 0
2 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
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