Answer:
B is the correct answer of this question
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
-6
Step-by-step explanation: 6 6 15 40
f(x) = –2 – 4, find f(4)
since there is NO x term in the function for ANY x
f(4) = –2 – 4 = -6
f(any x) = –2 – 4, find f(-∞ = x = ∞)
= -6
Answer:
190.67 ft/sec
Step-by-step explanation:
130 mi/hr x 5280 ft/mi x 1/60 hr/min x 1/60 min/sec = 190.67 ft/sec
It makes more sense if you write these as fractions and cancel units.
Answer:
8.34/1
Step-by-step explanation: