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3 years ago

What steps should be taken to calculate the volume of the right triangular prism? Select three options.

Mathematics

2 answers:

Marrrta [24]3 years ago

8 0

Answer:

a,d, and e

Step-by-step explanation:

Mariana [72]3 years ago

5 0

Answer:

Options A, D and E.

Step-by-step explanation:

Formula to calculate the volume of the triangular prism is,

Volume of the triangular prism = (Area of the triangular base)×(height)

= B × h

Area of the right triangular base = $\frac{1}{2}(\text{Base})(\text{height})$

= $\frac{1}{2}(8)(14)$

= 56 m²

Volume of the prism = $(56)(7)$

= 392 cubic meter

Therefore, from the given options correct options are Option A, Option D and Option E.

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What is the slope of the line that contains the points (-2,5) and (6, -3)?

mel-nik [20]

Answer:

-1

Step-by-step explanation:

Attached is a picture of slope formula:

1) Apply slope formula given two points:

(5--3)/(-2-6)

2) Simplify:

8/-8

3) Divide:

-1

3 0

3 years ago

Read 2 more answers

F(x)=2x^2-x-6 g(x)=4-x (f+g)(x)

Semenov [28]

$\large \boxed{(f + g)(x) = f(x) + g(x)}$

The property above is distribution property where we distribute x-term in the function.

Substitute both f(x) and g(x) in.

$\large{ \begin{cases} f(x) = 2 {x}^{2} - x - 6 \\ g(x) = 4 - x \end{cases}} \\ \large{f(x) + g(x) = (2 {x}^{2} - x - 6) + (4 - x)} \\ \large{f(x) + g(x) = 2 {x}^{2} - x - 6 + 4 - x}$

Évaluate/Combine like terms.

$\large{f(x) + g(x) = 2 {x}^{2} - 2x - 2}$

The function can be factored so there are two answers. (Both of them work as one of them is factored form while the other one is not.)

$\large{(f + g)(x) = 2 {x}^{2} -2x -2}$

<u>Alternative</u>

$\large{(f + g)(x) = 2({x}^{2} -x - 1)}$

<u>Answer</u>

(f+g)(x) = 2x²-2x-2
(f+g)(x) = 2(x²-x-1)

Both answers work. The second answer is in factored form.

Let me know if you have any doubts!

8 0

3 years ago

Pleeeeeese helppp!!!!!!!!!!!

Svetlanka [38]

I think 17.2 sorry if im wrong

7 0

3 years ago

Please help, only reply if you know answer

34kurt

Answer:

see explanation

Step-by-step explanation:

The translation represented by $\left[\begin{array}{ccc}1\\4\\\end{array}\right]$

interprets as a shift of 1 unit to the right ( add 1 to x- coordinate ) and a

shift of 4 units down ( subtract 4 from the y- coordinate ), then

(1, 4 ) → (1 + 1, 4 - 4 ) → (2, 0 )

(4, 4 ) → (4 + 1, 4 - 4 ) → (5, 0 )

(6, 2 ) → (6 + 1, 2 - 4 ) → (7, - 2 )

(1, 2 ) → (1 + 1, 2 - 4 ) → (2, - 2 )

8 0

3 years ago

Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.5 rad/s 2 has an angular velocity of 0 rad

Zigmanuir [339]

Answer:

$\theta = 5.83\ rad$

Step-by-step explanation:

given,

angular deceleration, α = -0.5 rad/s²

final angular velocity,ω_f = 0 rad/s

angular position, θ = 6.1 rad

angular position at 3.9 s = ?

now, Calculating the initial angular speed

$\omega_f^2 = \omega_i^2 + 2 \alpha \theta$

$0 = \omega_i^2 - 2\times 0.5\times 6.1$

$\omega_i = \sqrt{6.1}$

$\omega_i = 2.47\ rad/s$

now, angular position calculation at t=3.9 s

$\theta = \omega_i t + \dfrac{1}{2}\alpha t^2$

$\theta =2.47\times 3.9 - \dfrac{1}{2}\times 0.5\times 3.9^2$

$\theta = 5.83\ rad$

Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.

7 0

4 years ago