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3 years ago

Suppose you know that a line passes through the point (0,1).it's slope is 1. Find another point on the line.

Mathematics

1 answer:

tamaranim1 [39]3 years ago

4 0

I think it will probably be (0,2)

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In a water treatment plant, water passes through a cone-shaped filter with a height of 4 m and a diameter of 9 m. The water flow

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3 years ago

A newborn baby what weighs 3⁷ kilograms. An adult blue whale weighs 81 times the newborn. How many kilograms does the adult blue

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2187

Step-by-step explanation: 27 times 81 equals 2187

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2 years ago

Carole makes an array of magnets on her refrigerator she makes7 rows with 8 magnets in each row which of the following shows how

timofeeve [1]

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3 years ago

Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and

Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

$\angle EAC = \angle ACD = 90^{\circ}$

To prove :

$EB\times BD=AB\times BC$

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

$\triangle AEC \sim \triangle EBA$ ,

Similarly,

$\triangle AEC \sim \triangle ABC$

$\implies\triangle EBA\sim \triangle ABC-----(1)$

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

$\triangle ADC \sim \triangle CBD$ ,

Similarly,

$\triangle ADC \sim \triangle ABC$

$\implies \triangle CBD\sim \triangle ABC-----(2)$

From equations (1) and (2),

$\triangle EBA\sim \triangle CBD$

The corresponding sides of similar triangles are in same proportion,

$\frac{EB}{BC}=\frac{AB}{BD}$

$\implies EB\times BD=AB\times BC$

Hence, proved....

5 0

3 years ago

Draw a line representing the "rise" and a line representing the "run" of the line, State

Alexxx [7]

Answer:

The slope of the line m = 1

The equation of the straight line x -y -7=0

Step-by-step explanation:

Explanation:-

In the given graph

The points are ( 7,0) and ( 0, -7)

The slope of the line

$m = \frac{y_{2}- y_{1} }{x_{2}-x_{1} } = \frac{-7-0}{0-7} = \frac{-7}{-7} = 1$

The equation of the straight line passing through the point (7,0) and slope m=1

y - y₁ = m (x - x₁)

y - 0 = 1( x-7)

y = x -7

x - y -7=0

Final answer:-

The slope of the line m = 1

The equation of the straight line x -y -7=0

4 0

2 years ago