If there are 4 trucks then the first truck weighs x
then x+2tons
then x+4tons
then x+6tons = 32tons
so 4x+12=32
-12 -12
/4 /4
x=5
so plug it back in
truck 1= 5tons or 10,000lbs
truck 2= 7tons or 14,000lbs
truck 3= 9tons or 18,000lbs
truck 4= 11tons or 22,000lbs
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x and cos²x = 1 - sin²x
Consider the left side
← expand numerator/denominator using FOIL
=
= 
= 
= 
= cot²A = right side , thus proven
<span>6^1/3 * 6^1/4 = 6^x/y
The key to solving this problem is understanding properties of exponents:
If you are multiplying two powers with the same base (in this case the base is 6), the result is the base raised to the power of the two exponents added together.
6^1/3+1/4 = 6^x/y
6^7/12 = 6^x/y
So the product would be 6^7/12
x = 7
y = 12</span>
a²+b² = c² where a and b are legs and c is the hypotenuse
So...
a²+4²=13²
a²+16=169
a²=153
a=√153
answer: approx. 12.37 units
V = 576 pi cm^3
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
V = pi * (6)^2 * 16
V = pi *36*16
V = 576 pi cm^3