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liq [111]
3 years ago
6

explain how multiplying a whole number and a decimal is similar to and different from multiplying whole numbers

Mathematics
1 answer:
Mrac [35]3 years ago
6 0
It's similar because u still with have an answer weather its a decimal or not. And it's different because when your multiplying whole number u will just get whole numbers.
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F(x)=x^2. What is g(x)
xxTIMURxx [149]

Answer:

g(x) = \frac14x^2

Step-by-step explanation:

Since f(x) and g(x) share the same top at (0,0), their difference is only a scale factor, so g(x) = ax² but we need to find a.

To find it, we use the given point of g, (2,1)

So g(2) = 1

meaning that

a·2² = 1

4a = 1

a = 1/4

4 0
3 years ago
Mark wrote the highest score he made on his new video game as the product of 70x6,000. Use the associative and commutative prope
Lelu [443]
You need a caculater that is what you need tho

5 0
3 years ago
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In 1990, the rate of change of the world population was approximately 0.09125 billion per year (or approximately 1 million peopl
babunello [35]

Answer: Option A

P = 5.3 + 0.09125t

Step-by-step explanation:

Note that for the initial year, 1990, the population was 5.3 billion.

The exchange rate is 0.09125 billion per year. In other words, each year there are 0.09125 billion more people.

In year 2 there will be 0.09125 * 2 billion people

In year 3 there will be 0.09125 * 3 billion people

In year 4 there will be 0.09125 * 4 billion people

In year t there will be 0.09125 * t billion of people

So the equation that models the number of people that there will be as a function of time is:

P = P_0 + rt

Where P_0 is the initial population

P_0 = 5.3 billion

r is the rate of increase

r = 0.09125 billion per year

finally the equation is:

P = 5.3 + 0.09125t

The correct answer is option A.

6 0
4 years ago
Read 2 more answers
The The Laplace Transform of a function , which is defined for all , is denoted by and is defined by the improper integral , as
guapka [62]

Answer:

a. L{t} = 1/s² b. L{1} = 1/s

Step-by-step explanation:

Here is the complete question

The The Laplace Transform of a function ft), which is defined for all t2 0, is denoted by Lf(t)) and is defined by the improper integral Lf))s)J" e-st . f(C)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of s as a fixed constant) 1. Find Lft) (hint: remember integration by parts) A. None of these. B. O C. D. 1 E. F. -s2 2. Find L(1) A. 1 B. None of these. C. 1 D.-s E. 0

Solution

a. L{t}

L{t} = ∫₀⁰⁰e^{-st}t

Integrating by parts  ∫udv/dt = uv - ∫vdu/dt where u = t and dv/dt = e^{-st} and v = \frac{e^{-st}}{-s} and du/dt = dt/dt = 1

So, ∫₀⁰⁰udv/dt = uv - ∫₀⁰⁰vdu/dt w

So,  ∫₀⁰⁰e^{-st}t =  [\frac{te^{-st}}{-s}]₀⁰⁰ -  ∫₀⁰⁰ \frac{e^{-st}}{-s}

∫₀⁰⁰e^{-st}t =  [\frac{te^{-st}}{-s}]₀⁰⁰ -  ∫₀⁰⁰ \frac{e^{-st}}{-s}

= -1/s(∞exp(-∞s) - 0 × exp(-0s)) + \frac{1}{s} [\frac{e^{-st} }{-s}]₀⁰⁰

= -1/s[(∞exp(-∞) - 0 × exp(0)] - 1/s²[exp(-∞s) - exp(-0s)]

= -1/s[(∞ × 0 - 0 × 1] - 1/s²[exp(-∞) - exp(-0)]

= -1/s[(0 - 0] - 1/s²[0 - 1]

= -1/s[(0] - 1/s²[- 1]

= 0 + 1/s²

= 1/s²

L{t} = 1/s²

b. L{1}

L{1} = ∫₀⁰⁰e^{-st}1

= [\frac{e^{-st} }{-s}]₀⁰⁰

= -1/s[exp(-∞s) - exp(-0s)]

= -1/s[exp(-∞) - exp(-0)]

= -1/s[0 - 1]

= -1/s(-1)

= 1/s

L{1} = 1/s

6 0
3 years ago
The price of an item yesterday was $140. Today, the price fell to $63. Find the percentage decrease
DENIUS [597]

Answer:

it is a 55% decrease

(why do i have to type at least twenty characters, just send the answer omg)

8 0
3 years ago
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