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andriy [413]
3 years ago
6

Write the equation for the following relation. Q= {(x,y): (4,5), (8,7), (12,9), (16,11),...}​

Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

There's really no way to solve this problem apriori (unless you can use tools like lagrange polynomials to interpolate points), so I'll just tell you how to approach problems like this.

First of all, we may try to see if the dependence is linear: the input is always increased by 4 (4, 8, 12, 16,...) and the output increases by 2: (5, 7, 9, 11). So, the answer is yes.

Now that we know that these points lay on a line, we can conclude the exercise in several ways:

  1. We already know that the slope is 1/2 (4 units up in the x direction correspond to 2 units up in the y direction). So, we only need the y-intercept. If we go back one step, we can see that the next point would be (0, 3) (I decreased the x coordinate by 4 and the y coordinate by 2). So, the y intercept is 3, and the equation of the line is y=\frac{x}{2}+3
  2. We can use the equation of the line passing through two points:

\dfrac{x-x_2}{x_1-x_2}=\dfrac{y-y_2}{y_1-y_2}

Plug in two points of your choice and you'll get the same answer.

Of course, as a third alternative, you could just have eyeballed the answer: the fact that x grows twice as fast as y could have hinted the x/2 part, and then you could have seen that y is always 3 more than half of x, again leading to y=x/2+3.

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50 points
masha68 [24]

Answer:

Alaina

Step-by-step explanation:

Although I might be wrong on this I dont think I am as it is the closest to -1 while being the farthest from -2

7 0
3 years ago
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0.285714285 nearest thousandth​
Agata [3.3K]

Answer:

0.286

Hope that helps!

Step-by-step explanation:

3 0
3 years ago
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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Mom is 8 years older than 4 times Sarah’s age. The sum of their ages is less than 83. What is Sarah’s oldest possible age?
tigry1 [53]

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3 0
3 years ago
Find the least common multiple of 8b^2 and 5n^3
muminat

Answer:

The lcm is; 40b^2n^3

Step-by-step explanation:

There are no common factors between the two expressions and as such the lcm will be found by obtaining the product of he two;

8b^2*5n^3 = 40b^2n^3

5 0
3 years ago
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