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marysya [2.9K]
4 years ago
6

Suppose you pay $3.00 to roll a fair die with the understanding that you will get back $5.00 for rolling a 1 or a 6, nothing oth

erwise. What is your expected value?
Mathematics
1 answer:
Andru [333]4 years ago
4 0
<span><span> 1 down vote accepted </span> <span> The expected value is the sum of the probablity of each outcome multiplied by the "value" of each outcome. Its sort of like a special average. In your case each outcome has probability <span>16</span></span></span>

. and you get 5 dollars when you roll 3 or 6 when you roll something else.

So the expected value is

<span><span>06</span>+<span>06</span>+<span>56</span>+<span>06</span>+<span>06</span>+<span>56</span>=<span>106</span>=<span>53</span></span>

.

This means loosely that if you played this game a lot you should expect to win on average about 1.66 dollars, while you payed 3 to play it. Clearly this is a great idea if you want to lose money.


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Write an equation for the translation of x^2 + y^2 = 49 by 7 units right and 4 units up
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Answer:

(x - 7)² + (y - 4)² = 49

Step-by-step explanation:

Given

Equation: x² + y² = 49

Required:

New Equation when translated 7 units right and 4 units up

Taking it one step at a time.

When the equation is translated 7 units right, this implies a negative unit along the x axis.

The equation becomes

(x - 7)² + y² = 49

When the equation is translated 4 units up, this implies a negative unit along the y axis.

(x - 7)² + (y - 4)² = 49

The expression can be further simplified but it's best left in the form of

(x - 7)² + (y - 4)² = 49

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Answer:

Store A and it would cost $32.40 (answer choice A)

Step-by-step explanation:

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In store BA: (13 balloons for $16.25) then per each balloon: $16.25/13 = $1.25 per balloon.

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Answer:

R1:   Given

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