All categories

3 years ago

What can you infer about the population from each data set represented below?

Mathematics

1 answer:

-BARSIC- [3]3 years ago

8 0

The population seems like a young age group.

You might be interested in

John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs

mezya [45]

Answer:

The number of Pumpkin can used = 48 cans

The number of Green Beans can used = 16 cans

Step-by-step explanation:

The ratio of Pumpkin to Green Beans = 3 : 1

So, for every 3 can of Pumpkin, 1 can of green beans is used.

Now, the total number of John wants to use = 64

Let us assume the common factor in the ratio is m.

⇒ The number of Pumpkin can used = 3 m

The number of Green Beans can used = 1 m = m

So, the Total cans used = Number of (Pumpkin + Green Beans) can

⇒ 3 m + m = 64

or, 4 m = 64

⇒ m = 64/ 4 = 16

Hence, The number of Pumpkin can used = 3 m = 3 x 16 = 48 cans

The number of Green Beans can used = m = 16 cans

3 0

3 years ago

3(4 + Зр) How do u solve this?

xxTIMURxx [149]

12 + 9p distribute the 3

3 0

3 years ago

Which of the following is rational 9/12 or -64

natali 33 [55]

9/12 bc it is a fraction

3 0

3 years ago

You have $1 and $5 bills in your savings envelope with a total value of $26. there are more $1 bills than $5. you would like to

marta [7]

I’m not very good at math, but maybe try adding all of them together

3 0

3 years ago

The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of

ycow [4]

The length of the longer base is 41 ft.

Explanation

Lets assume, length of one base is $x$ ft.

As, another base is 19 less than five times the length of this base, so the length of another base $= (5x- 19) ft.$

The trapezoid has a height of 18 ft and area of 477 ft²

Formula for Area of trapezoid, $A=\frac{1}{2} (a+b)*h$ , where $a, b$ = Two bases of trapezoid and $h$ = height of the trapezoid.

Given in the question: $A= 477$ and $h= 18$

We have also two bases as: $a= x$ and $b= 5x-19$

So, according to the above formula...

$A= \frac{1}{2}(a+b)h\\\\ 477=\frac{1}{2}(x+5x-19)*18\\\\ 477=9(6x-19)\\\\477= 54x-171\\\\477+171=54x\\\\648=54x\\\\x=\frac{648}{54} = 12$

So, length of one base is $12 ft$ and another base $=(5*12-19)ft =(60-19)ft = 41 ft$

That means, the length of the longer base is 41 ft.

8 0

3 years ago