Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.


Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as

by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because

is a polynomial).
Answer is
0.8(2x-6)
Step-by-step explanation:
0.8x2x=1.6x
0.8x-6 = -4.8
we are given

Since, every value is in ft
so, we can take out ft

now, we can add them
and we get
............Answer
Answer:
x-int: (3, 0)
y-int: (0, 2)
Step-by-step explanation:
The x-int is found when y = 0. Set <em>y</em> to 0 to solve for the x-int.
The y-int is found when x = 0. Set <em>x</em> equal to 0 to solve for the y-int.
1. 5/6
2. 7/1
3. 1/7
Just write the first number as the numerator and the second one as a denominator then divide by their common factors