Answer:
$6 = cost of small box
$8 = cost of large box
Step-by-step explanation:
Let s = cost of small box
l = cost of large box
(1) 12s + 3l = 96 (2) 6s + 6l = 84
Multiply by -2 <u> -24s - 6l = -192</u>
-18s = - 108
s = $6 = cost of small box
12(6) + 3l = 96
72 + 3l = 96
3l = 24
l = $8 = cost of large box
Answer:
a. The time to strike the ground is 5 seconds
b. The time for the ball to be over than 96 ft is 1 second
Step-by-step explanation:
a. When the ball thrown vertically up ward to reach its maximum height at velocity = 0 then complete its motion vertically down ward to strike the ground its displacement = zero
∴ s(t) = 0 ⇒
∴
5 - t = 0⇒ ∴ t = 5 seconds
b. To tind the time that the ball will be over 96 ft over the ground substitute in
t = 3 sec. and t = 2 sec.
The ball will be at height 96 ft at time 2 sec. and 3 sec.
So the ball will be at height over than 96 = 3 - 2 = 1 sec.
H=(√3)*a/2 = 41.2
So, a=2*41.2/√3=47.6
Answer:
Yes, lines CD & AB are perpendicular
Step-by-step explanation:
AB slope: y = -12/8x + 7
CD slope: y = 6/9x - 6
Once the slopes are simplified:
AB: -3/2
CD: 2/3
Hope this helps!