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Vaselesa [24]
4 years ago
10

Please answer this question correctly

Mathematics
1 answer:
Levart [38]4 years ago
5 0
She has 224 ounces, which I claim is the correct answer. How will you know ?
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Find the constant of variation k for the direct variation ​
Alla [95]

Answer:

The constant of variation is k = -2 ⇒ (B)

Step-by-step explanation:

The equation of the direct variation is y = k x, where

  • k is the constant of variation
  • The constant of variation k = \frac{y}{x}

The given table has 4 points (-1, 2), (0, 0), (2, -4), (5, -10)

We can use one of the points <em>[except point (0, 0)]</em> to find the value of k

∵ (-1, 2) is a given point

∴ x = -1 and y = 2

∵ k = \frac{y}{x}

→ Substitute the values of x and y in the relation above

∴ k = \frac{2}{-1}

∴ k = -2

The constant of variation is k = -2

7 0
4 years ago
Round 7.76 to one decimal place
Gelneren [198K]
So if a number is 5 or greater you round up but if the number is 4 or less you round down so the number 6 is above five so you would round the 6 to 10 therefore making it 7.8 instead of 7.76
5 0
4 years ago
What is the difference between a two-dimensional sketch and an isometric sketch?
Nitella [24]
<span>I believe it is that a two-dimensional sketch doesn't include depth however the isometric sketch does</span>
7 0
4 years ago
3m-4n-7<br> 8m+n-6<br> Subtract the following polynomials
KATRIN_1 [288]

Answer:

5m - 5n - 1

Step-by-step explanation:

(3m - 4n - 7) - (8m + n - 6) =

3m - 4n - 7 - 8m - n + 6 =

5m - 5n - 1

7 0
3 years ago
A barber’s chair with a person in it weighs 2118.0 N. The output plunger of a hydraulic system begins to lift the chair when the
liq [111]

Answer:5.8

Step-by-step explanation:

Given

weight of chair with person on it =2118 N

Barber applies a force of 63 N

Using pascal's law

we know pressure around both sides is equal

i.e. P_{chair}=P_{piston}

pressure=\frac{force}{area}

P_{chair}=\frac{2118}{\pi \dot r_{plunger}^2}

P_{piston}=\frac{63}{\pi \dot r_{piston}^2}

substituting values

\left [\frac{r_{plunger}^2}{r_{piston}^2}\right ]=\frac{2118}{63}

\left [\frac{r_{plunger}}{r_{piston}}\right ]=\left [ \frac{2118}{63}\right ]^{0.5}

\left [\frac{r_{plunger}}{r_{piston}}\right ]=5.798

5 0
4 years ago
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