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Vaselesa [24]
3 years ago
10

Please answer this question correctly

Mathematics
1 answer:
Levart [38]3 years ago
5 0
She has 224 ounces, which I claim is the correct answer. How will you know ?
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In Richmond, Chloe ordered $40 worth of sushi. She knew that when the bill came, she would need to pay Richmond sales tax for 5%
maks197457 [2]

Answer:

$50

Step-by-step explanation:

Given data

Cost of sushi= $40

Tax= 5%

Tip= 20%

Let us find the amount of the tax and the tip

Tax

=5/100*40

=0.05*40

=$2

Tip

=20/100*40

=0.2*40

=$8

Hence the total amount paid is

=40+2+8

=$50

6 0
3 years ago
Ok so do I subtract 5 from x and 5 Orr am I solving wrong i don’t know this is confusing.
Aleksandr [31]

Answer:

no you dont

Step-by-step explanation:

4 0
2 years ago
Determine the value of x to the nearest thousandth in the equation 8(2)^x+3=48
solong [7]

You probably mean either

8\cdot2^x + 3 = 48

or

8\cdot2^{x+3} = 48

Write 8 = 2³, so that in the first interpretation,

8\cdot2^x = 2^3 \cdot 2^x = 2^{x + 3}

and in the second,

8\cdot2^{x+3} = 2^3 \cdot 2^{x+3} = 2^{x + 6}

Then in the first interpretation, we have

2^{x + 3} + 3 = 48 \implies 2^{x + 3} = 45 \implies x + 3 = \log_2(45) \implies x = \log_2(45) - 3 \approx \boxed{2.492}

Otherwise, the second interpretation gives

2^{x + 6} = 48 \implies x + 6 = \log_2(48) \implies x = \log_2(48) - 6 \approx -0.415

8 0
2 years ago
Hello, can u help me out please i will give brainlist :)
aalyn [17]

Answer:

$5.75

Step-by-step explanation:

Find the difference between the weeks as this will give you the difference hence the amount deposited each week

0->1

is 12.00->17.75

diffrence is $5.75

1->2

is 17.75->23.50

diffrence is  $5.75

the amount saved each week is $5.75

6 0
2 years ago
Y''+Y'+Y=1<br> solve ordinary differential equation
taurus [48]

Answer:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

Step-by-step explanation:

y" + y' + y = 1

This is a second order nonhomogenous differential equation with constant coefficients.

First, find the roots of the complementary solution.

y" + y' + y = 0

r² + r + 1 = 0

r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)

r = [ -1 ± √(1 − 4) ] / 2

r = -1/2 ± i√3/2

These roots are complex, so the complementary solution is:

y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)

Next, assume the particular solution has the form of the right hand side of the differential equation.  In this case, a constant.

y = c

Plug this into the differential equation and use undetermined coefficients to solve:

y" + y' + y = 1

0 + 0 + c = 1

c = 1

So the total solution is:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

To solve for c₁ and c₂, you need to be given initial conditions.

5 0
2 years ago
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