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3 years ago

What is the difference of the polynomials?

Mathematics

2 answers:

ser-zykov [4K]3 years ago

8 0

subtract the 2 x^4's

x^3 +x^3 = 2x^3

x +x = 2x

answer is 2x^3 + 2x

larisa [96]3 years ago

3 0

Answer:

2x^3 + 2x

Step-by-step explanation:

subtract the 2 x^4's

x^3 +x^3 = 2x^3

x +x = 2x

answer is 2x^3 + 2x

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What is the answer 7÷5,631 eqall

otez555 [7]

7/5,631=0.0012431185

3 0

3 years ago

Luke has $21 more than Rachel and $48 more than Daniel. All together they have $

KengaRu [80]

This can be solve by 3 variable equation
let x be the money of luke
y money of rachel
z money of daniel
first equation
x = y + 21
second equation
x = z + 48
third equation
x + y + z = 168
solving simultaneously
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3 0

4 years ago

The principal of East High School wants to buy a new cover for the sand pit used in the long-jump competition. He measured the s

Ganezh [65]

Answer: area is 286.16 ft²

Step-by-step explanation:

Length of the sand pit is 29.2 feet and the width is 9.8 feet.

L= 29.2 ft

W = 9.8 ft

To find out the area, all we have to do is multiply the lenght by the width:

And do not forget that to calculate the area, all units must be the same and for the area, it is always the unit squared, in this case, feet square or simply (ft²).

A = l*w

A = 29.2 * 9.8 = 286.16 ft²

3 0

3 years ago

Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective

soldier1979 [14.2K]

Answer:

a) $P[C]=p^n$

b) $P[M]=p^{8n}(9-8p^n)$

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

$P[C]=p^n$

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

$P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)$

$P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9$

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

$P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2$

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.