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Ede4ka [16]
2 years ago
12

darrel wants to see how much water is wasted by his leaky facet. he put a 4 gallon bucket under the fausey. after 24 hours the b

ucket was full. if the same amount of water leaks each hour how much water will be in the bucket after 70 hours?
Mathematics
1 answer:
aleksley [76]2 years ago
6 0

Answer:

The quantity of water filled in the bucket after 70 hours is 11.67 gallon  .

Step-by-step explanation:

Given as :

The quantity of water filled in the bucket after 24 hours = 4 gallon

Let The quantity of water filled in the bucket after 70 hours = x gallon

So, According to question

<u>Applying unitary method</u>

∵In 24 hours, The quantity of water filled in bucket = 4 gallons

So,In 1 hour, The quantity of water filled in bucket = \dfrac{4}{24} gallon

∴ In 70 hour, The quantity of water filled in bucket = \dfrac{4}{24} × 70 gallon

I.e x = \frac{4\times 70}{24} gallons

Or, x = 11.67 gallons

So,The quantity of water filled in the bucket after 70 hours = x = 11.67 gallon

Hence, The quantity of water filled in the bucket after 70 hours is 11.67 gallon  . Answer

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A random number generator is used to select an integer from 1 to 3 inclusive. What is the difference between the estimated proba
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Step-by-step Answer:

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2 years ago
A sailboat depreciates at 15% of its original value each year. If the sailboat was $9500 at its time of purchase, what is the va
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Answer: After 7 years, the value of the sailboat is $3045.49.

Step-by-step explanation:

Since we have given that

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Depreciation rate = 15%

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As we know the formula for "Compound Interest "i.e

A=P(1-\frac{r}{100})^n

where,

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So, our equation becomes ,

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6 0
3 years ago
Read 2 more answers
Which second degree polynomial function f(x) has a lead coefficient of 3 and roots 4 and 1?
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For this case we have that the following function complies with the given conditions:

f (x) = 3x ^ 2 - 15x + 12

To prove it, let's find the roots of the polynomial:

3x ^ 2 - 15x + 12 = 0

By doing common factor 3 we have:

3 (x ^ 2 - 5x + 4) = 0

Factoring the second degree polynomial we have:

3 (x-1) (x-4) = 0

Then, the solutions are:

Solution 1:

x-1 = 0\\x = 1

Solution 2:

x-4 = 0\\x = 4

Answer:

A second degree polynomial function f (x) that has a lead coefficient of 3 and roots 4 and 1 is:

f (x) = 3x ^ 2 - 15x + 12

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