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Vaselesa [24]
3 years ago
14

X / 2.5 = 10 plz helppp

Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

x=25

Step-by-step explanation:

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Find the mean of the distribution class 1-3 3-5 5-7 7-9. frequency 9 22 27 17<br> ​
yan [13]

Answer:

Hope this helps you

Step-by-step explanation:

Mean= \frac{404}{75} = 5.386666666666667

Therefore, the mean of the given distribution =5.39 or 3.4

If you did not understand anything you can ask in the comments

6 0
2 years ago
PLEASE HELP I REALLY APPRECIATE IT AND NEED IT.
Oksanka [162]

Problem 5

Each two tangents form a right angle from the center of the circle to the circumference (a radius) and from the circumference to the exterior point. That makes a kite of 2 tangents and 2 radii.

The radii make an angle of 360 - 2*90 - 47 = 133.

That is also the central angle for the arc you are asking about.

Answer: 133.

Problem 9

The center is at point (-6, - 8) So far what you have is

(x + 6)^2 + (y + 8)^2 = r^2

You use the two given points to find r^2

r^2 = (x2 - x1)^2 + (y2 - y1)^2

r^2 = (-6 - 0)^2 + (- 8 - 0)^2

r^2 = 36 + 64

r^2 = 100

The circles equation is (x + 6)^2 + (y + 8)^2 = 100

Answer D

7 0
3 years ago
74.6993975879 to one decimal place???
lana [24]

Answer:

75.7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The path of a satellite orbiting the earth causes the satellite to pass directly over two tracking stations A and B, which are 9
Gre4nikov [31]

Answer:

A) 585 miles

B) 584 miles

Step-by-step explanation:

We are told that the satellite pass directly over two tracking stations A and B, which are 90 mi apart.

This means that we can look at this as forming a kind of triangle where Tracking stations A & B will be

opposite ends of the base of the triangle while the satellite position will be the apex of the triangle.

We are given the angles of elevation at A and B to be 87.0° and 84.2° respectively.

Now, if we depict the satellite position as C. Then we have;

Angle at C = 180 - (87 + 84.2)

Angle at C = 8.8°

I've attached an image depicting this triangle.

A) To find the distance of the satellite from Station A, from the image attached, the distance will be AC.

Since AB is 90 mi.

Thus, using sine rule, we have;

AB/sin C = AC/sinB

Plugging in the relevant values;

90/(Sin 8.8) = AC/(sin 84.2)

AC = (90 × (sin 84.2))/(Sin 8.8)

AC = 585.27

To the nearest mile gives;

AC = 585 miles

B) To find out how high the satellite is above the ground, is the perpendicular distance from point C to line AB

Let's call the point at which the line touches AB as D.

It means angle D is 90° and it means triangle ADC it's a right angled triangle where AC is the hypotenuse = 585 miles.

Thus, using Trigonometric ratios we can find CD

Sin(87) = CD/585

CD = (Sin 87) x 585

CD = 584.198 miles

Approximating to the nearest mile gives;

CD = 584 miles

5 0
3 years ago
I need help on this asap
svet-max [94.6K]

Answer:

6

Step-by-step explanation:

I got 6 but I’m not totally sure if its right

7 0
3 years ago
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