The area will be half the product of the lengths of AB and CD.
|AB| = √((6-1)² +(-2-3)²) = 5√2
|CD| = √((5-2)² +(5-2)²) = 3√2
Area = (1/2)*(5√2)*(3√2) = (1/2)*(15*2) = 15
The appropriate choice is ...
D: 15 square units
V=hpir^2
c=2pir
assuming they havve same height
first one is
v=hpi5^2
v=25hpi
2nd one
c=2pir=20pi
2pir=20pi
2r=20
r=10
v=hpir^2
v=hpi10^2
v=100hpi
big/small=100hpi/25hpir=4
4 times greater
Answer:
0.9562
Step-by-step explanation:
Binomial probability is mathematically expressed as:
Given that p=0.18, n=5 , is calculated as:
Hence, the probability of no more than 2 successes in 5 trials is 0.9562
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
