For this case we use the following formula
Area of Sector = Area * radians of sector / 2 * pi radians
Where,
Area: it is the area of the complete circle.
We have then:
Area = pi * r ^ 2
Area = pi * (6) ^ 2
Area = 36pi
Substituting values:
5pi = 36pi * radians of sector / 2 * pi
Clearing:
radians of sector = ((5pi) * (2pi)) / (36pi)
radians of sector = (10pi ^ 2) / (36pi)
radians of sector = (10pi) / (36)
radians of sector = (10/36) pi
radians of sector = (5/18) pi
in degrees:
(5/18) pi * (180 / pi) = 50 degrees
Answer:
The measure of the central angle is:
50 degrees

3 0

3 years ago

Without further study, you forget things as time passes. A model of human memory gives the percentage, p, of acquired knowledge

PIT_PIT [208]

Answer:

42.69% of information is acquired by the student in two weeks.

Step-by-step explanation:

We are given the following in the question:

$p = (100 -a)e^{-bt} + a$

where a and b are constants.

$a = 18\\b = 0.6$

p tells us about the percentage of acquired knowledge that a person retains after t weeks.

We have to find the percentage of knowledge acquired in two week.

We put t = 2

$p = (100 -18)e^{-(0.6)(2)} + 18\\p = 42.69$

Thus, 42.69% of information is acquired by the student in two weeks.

5 0

3 years ago

2log(2a - 1) = 0<br> How

Kryger [21]

Answer:

Step-by-step explanation:

$2\log(2a-1)=0\\\\\text{Domain:}\\\\2a-1>0\qquad\text{add 1 to both sides}\\2a-1+1>0+1\\2a>1\qquad\text{divide both sides by 2}\\\dfrac{2a}{2}>\dfrac{1}{2}\\\boxed{a>0.5}\\============================\\\\2\log(2a-1)=0\qquad\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup\log(2a-1)}{2\!\!\!\!\diagup}=\dfrac{0}{2}\\\\\log(2a-1)=0\qquad\text{use}\ \log_ab=c\iff b=a^c\\\\\log(2a-1)=\log10^0\\\\\log(2a-1)=\log1\iff2a-1=1\qquad\text{add 1 to both sides}\\\\2a-1+1=1+1\\\\2a=2\qquad\text{divide both sides by 2}\\\\\dfrac{2a}{2}=\dfrac{2}{2}\\\\a=1\in D$

3 0

2 years ago