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3 years ago

9. The length of each side of a square with area 2500 square inches is increased by 10 inches. What

Mathematics

1 answer:

shusha [124]3 years ago

7 0

Answer: 3600

Step-by-step explanation:

Area of a square = side^2

Area = √2500 = 50

If side is increased by 10, length if side becomes 60 inches

Area = 60^2

Area = 3600 sq. in.

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Anestetic [448]

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2 years ago

Find x from given equations sin30 + 2 cot^2 30 + x cos^2 30= 8+ tan^2 45 + cos 60

julia-pushkina [17]

Answer

1/2+2×(sqrt3)^2+x.(sqrt3/2)^2=8+1^2+1/2

1/2+2×3+x.3/4=8+1+1/2

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x.3=3×4

x.3=12

x=12/3

x=4.

so, the value of x is 4.

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2 years ago

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2 years ago

A square has a perimeter of 36 millimeters.<br> What is the area of the square?

Nana76 [90]

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Step-by-step explanation:

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2 years ago

Drag the tiles to the correct boxes to complete the palrs.

Brut [27]

Answer:

(f+g)(2) = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

$f(x) = 2x + 3$

$g(x) = x - 1$

(f+g)(2)

$(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2$

At $x = 2$

$(f+g)(2) = 3(2) - 2 = 6 - 2 = 4$

Then

(f+g)(2) = 4

(f-g)(4)

$(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4$

At x = 4

$(f-g)(4) = 4 + 4 = 8$

Then

(f-g)(4) = 8

(f ÷g)(2)

$(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}$

At x = 2

$(f \div g)(2) = \frac{7}{1} = 7$

Then

(f ÷g)(2) = 7

(f x g)(1)

$(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3$

Then

$(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0$

(f x g)(1) = 0

4 0

2 years ago