What property is shown here? 2 + (-3) = (-3) + 2

Mathematics

2 answers:

expeople1 [14]2 years ago

4 0

Answer:

It's commutative property

Murljashka [212]2 years ago

3 0

Answer:

The Associative Properties of Addition

Step-by-step explanation:

The associative property of addition tells us that numbers' order can be switched around without altering the final result.

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What is the domain (in interval notation) of the following functions?

alexgriva [62]

$1.\\g(x)=\frac{3}{5x-4}\\\\D:5x-4\neq0\to5x\neq4\ \ \ /:5\to x\neq\frac{4}{5}\to x\in\mathbb{R}\ \backslash\ \{\frac{4}{5}\}\\\\2.\\h(x)=\frac{\sqrt{x}}{x-5}\\\\D:x\geq0\ \wedge\ x-5\neq0\to x\geq0\ \wedge\ x\neq5\to x\in\left$

$3.\\f(x)=\frac{\sqrt{x}}{x^2-5x}\\\\D:x\geq0\ \wedge\ x^2-5x\neq0\to x\geq0\ \wedge\ x(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq0\ \wedge\ x\neq5\to x\in\mathbb{R^+}\ \backslash\ \{5\}\\\\4.\\g(x)=\frac{\sqrt{x}+5}{x^2-x-20}\\\\D:x\geq0\ \wedge\ x^2-x-20\neq0\to x\geq0\ \wedge\ (x+4)(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq-4\ \wedge\ x\neq5\to x\in\left$

$5.\\h(x)=\frac{3}{x^2+1}\\\\D:x^2+1\neq0\to x^2\neq-1\to x\in\mathbb{R}\\\\6.\\f(x)=\frac{\sqrt{x-2}}{x+1}\\\\D:x-2\geq0\ \wedge\ x+1\neq0\to x\geq2\ \wedge\ x\neq-1\to x\in\left$

$7.\\g(x)=\frac{x^2}{3x^2-x-2}\\\\D:3x^2-x-2\neq0\to (3x+2)(x-1)\neq0\to x\neq-\frac{2}{3}\ \wedge\ x\neq1\\\\\to x\in\mathbb{R}\ \backslash\ \{-\frac{2}{3};\ 1\}\\\\8.\\h(x)=3(x-4)^2-7\\\\D:x\in\mathbb{R}$

4 0

2 years ago

I need help :( i don't understand this

maria [59]

Answer: 116.93ft^2

Explanation: find the area of the circle
A= pi•r^2
A=(3.14)•1.5^2= 7.07

Then find the area of the rectangle
A=L•W
A=15.5•8=124

Then do 124-7.07=116.93

You have to subtract the area of the circle from the area of the rectangle because the circle is not shaded in

4 0

3 years ago

Calculate the distance between the points P=(-1, -1) and L=(6, -9) in the coordinate plane.

Over [174]

Answer:

≈ 10.63

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$