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3 years ago

7

The water level in the aquarium's shark tank is always greater than 25 feet. If the water level decreased by 6 feet during clean

ing, what was the water level before the cleaners took out any water.
Please write an inequality to solve the problem please

1 answer:

Whitepunk [10]3 years ago

8 0

Answer:31

Step-by-step explanation:25 +6

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HELP, i’m not good a triangles

seraphim [82]

Answer:

B

Step-by-step explanation:

SSS stand for Side Side Side, so the truangle must identify all it's sides. To identify sides it uses lines through the side like in B where 1 side has 1 line, 1 side has 2 lines, and the other side has 3 lines. That is the side identifiers, and because each side in B matches with 1 side in A, means that A and B are congruent because they have the same sides, so SSS.

This is confusing to explain, if you have any questions post them in the comments.

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Can y’all help me me on question 2?! Have a good day!

AfilCa [17]

Answer:

9

Step-by-step explanation:

The formula to get the area of a triangle is A= $\frac{(b)(h)}{2}$ so all you have to do is work backwards. 18x2=36. 36/4=9.

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3 years ago

Jack bought 4 bagels for 3.00. how many bagels can he buy for 4.50?

bija089 [108]

Answer:

The answer is

<h2>6 bagels</h2>

Step-by-step explanation:

In order to solve this problem we use ratio and proportion

From the question

He used 3.00 to buy 4 bagels

Then 4.50 will be

$\frac{4.5 \times 4}{3} \\ = \frac{18}{3}$

We have the final answer as

<h3>6 bagels</h3>

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3 years ago

Read 2 more answers

Find the product of (2x-3) and (x+3)

miss Akunina [59]

Answer:

(2x - 3) * (x + 3)

=> (2x * x) + (-3 * 3)

=> 2x - 9

=> 2x -9

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3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago