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Semenov [28]
3 years ago
5

a passenger train leaves a train depot 2.5 after a freight train leaves the same depot the passenger train is traveling 13 mph f

aster than the freight train. find the rate of each train if the passenger train overtakes the freight in 5 h
Mathematics
1 answer:
Leona [35]3 years ago
8 0

Answer:

Freight = 13 mph

Passenger = 26 mph

Step-by-step explanation:

Givens

<em><u>Freight Train</u></em>

Rate = r

time = 5 hours

distance = 5*r

<em><u>Passenger Train</u></em>

r = r + 13

t = 2.5 hours

d = (r + 13)*2.5

Formula

The distances are the same so the rate times the time can be equated.

(r + 13) * 2.5 = 5*r            

Solution

Divide both sides by 2.5

(r + 13)*2.5 / 2.5 = 5* r / 2.5

r + 13 = 2r                              Subtract r from both sides.

r - r + 13 = 2r - r

13 = r                                     Switch and divide by 1.5

r = 13                                     Freight train

r + 13 = 13 + 13 = 26 mph.    Passenger train.

Both trains traveled a distance of 65 miles.  See if you can see why.


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3 years ago
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Answer:

a) The probability tree is constructed below

b) the probability that at least two women will be selected is 0.500

Step-by-step explanation:

Given the data in the question;

a) The probability tree is as follows;

                                                 3 men, 3 women

                                                            ↓

           _______________________|________________________

            ↓                             ↓                                  ↓                               ↓

         3 men                    2 men                          1 man                        0 men

      0 women                1 woman                     2 woman                   3 women

b) the probability that at least two women will be selected

p( at least two women would be selected) = P( there are 2 women out of 3 ) + P( there 3 women out of 3

so

p( at least two women would be selected) = C

³C₂ × ³C₁ / ⁶C₃ + ³C₃³C₀ / ⁶C₃  

= 3!/(2!(3-2)!) × 3!/(1!(3-1)!)  / 6!/(3!(6-3)!) + 3!/(3!(3-3)!) × 3!/(0!(3-0)!) / 6!/3!(6-3)!)

= 3 × 3 / 20 + 1 ×  1 / 20

= 9/20 + 1/20

= 0.45 + 0.05

p( at least two women would be selected) = 0.500

Therefore, the probability that at least two women will be selected is 0.500

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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