Answer:
Freight = 13 mph
Passenger = 26 mph
Step-by-step explanation:
Givens
<em><u>Freight Train</u></em>
Rate = r
time = 5 hours
distance = 5*r
<em><u>Passenger Train</u></em>
r = r + 13
t = 2.5 hours
d = (r + 13)*2.5
Formula
The distances are the same so the rate times the time can be equated.
(r + 13) * 2.5 = 5*r
Solution
Divide both sides by 2.5
(r + 13)*2.5 / 2.5 = 5* r / 2.5
r + 13 = 2r Subtract r from both sides.
r - r + 13 = 2r - r
13 = r Switch and divide by 1.5
r = 13 Freight train
r + 13 = 13 + 13 = 26 mph. Passenger train.
Both trains traveled a distance of 65 miles. See if you can see why.