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shusha [124]
3 years ago
11

How can i simplify this 32/3-3

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0
You can’t simplify it.
32/(3-3)
3 subtracted by 3 is 0.
But 32/0 will only be undefined because no number multiplied by 0 will get you 32.
So there is no actual number for it.

Answer: Unable to simplify. (Undefined)
Nikolay [14]3 years ago
3 0

Answer:

Step-by-step explanation:

well, if 3-3 is 0, then it is just 32.

I hope I got it right!

☾Lalita

p.s, it might be wrong.....

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What is the solution to this inequality?
Snezhnost [94]

Answer:

  • \boxed{\sf{D. \quad x < 3}}

Step-by-step explanation:

It is necessary to isolate the term of x from one side of an inequality to find its solution.

<h3>-4x-8>-20</h3>

<u>First, add by 8 from both sides.</u>

\sf{-4x-8+8 > -20+8}

<u>Solve.</u>

-20+8=-12

<u>Rewrite the problem down.</u>

\sf{-4x > -12}

<u>Multiply by -1 from both sides.</u>

(-4x)(-1)<(-12)(-1)

<u>Solve.</u>

<u>Multiply the numbers from left to right.</u>

(-12)(-1)=12

4x<12

<u>Divide by 4 from both sides.</u>

4x/4<12/4

<u>Solve.</u>


<u>Divide the numbers from left to right.</u>

12/4=3

<u>x<3</u>

  • <u>Therefore, the correct answer is D. x<3 (last option).</u>

I hope this helps you! Let me know if my answer is wrong or not.

5 0
2 years ago
Read 2 more answers
Helen got a 7% reduction in the price of pair jeans that are normally $32. What is the approximate percent decrease in the price
Colt1911 [192]

A percentage is a way to describe a part of a whole. The approximate percent decrease in the price is 21.87%, thus, the correct option is B.

<h3>What are Percentages?</h3>

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

Given the reduction in the price is $7, while the original cost is $32. Therefore, the approximate percent decrease in the price is,

Percentage decrease = 7/32  × 100%

                                     = 21.87%

Hence, the approximate percent decrease in the price is 21.87%, thus, the correct option is B.

The correct question is:

Helen got a $7 reduction in the price of a pair of jeans that are normally $32. What is the approximate percent decrease in the price?

The percent decrease is approximately 15%.

The percent decrease is approximately 21%.

The percent decrease is approximately 43%.

The percent decrease is approximately 78%

Learn more about Percentages:

brainly.com/question/6972121

#SPJ1

3 0
2 years ago
The graph of a quadratic function does not cross the x-axis, but crosses the y-axis in one place.
natulia [17]

Answer: D


Step-by-step explanation:

A quadratic function has a degree of 2 so there will be two roots.  The statement says the function does NOT CROSS THE X-AXIS so there are no real roots. That means both roots must be imaginary (complex).

5 0
3 years ago
Find the area of a circle with a circumference of 18.84 units
Nata [24]

Answer:

278.773622 or 300 if rounded

Step-by-step explanation:

The area of a circle is:

π (Pi) times the Radius squared:

A = π r2

or, when you know the Diameter:

A = (π/4) × D2

or, when you know the Circumference:

A = C2 / 4π

6 0
3 years ago
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
salantis [7]

Answer:

With​ 90% confidence, it can be said that the population mean price lies in the first interval. With​ 95% confidence, it can be said that the population mean price lies in the second interval. The​ 95% confidence interval is wider than the​ 90%.

Step-by-step explanation:

We are given that a random sample of 60 home theater systems has a mean price of​$131.00. Assume the population standard deviation is​$18.80.

  • Firstly, the pivotal quantity for 90% confidence interval for the  population mean is given by;

                            P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean price = $131

            \sigma = population standard deviation = $18.80

            n = sample of home theater = 60

            \mu = population mean

<em>Here for constructing 90% confidence interval we have used One-sample z test statistics as we know about the population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                   of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                                  = [131-1.645 \times {\frac{18.8}{\sqrt{60} } } , 131+1.645 \times {\frac{18.8}{\sqrt{60} } } ]

                                                  = [127.01 , 134.99]

Therefore, 90% confidence interval for the population mean is [127.01 , 134.99].

  • Now, the pivotal quantity for 95% confidence interval for the  population mean is given by;

                            P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean price = $131

            \sigma = population standard deviation = $18.80

            n = sample of home theater = 60

            \mu = population mean

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about the population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                                  = [131-1.96 \times {\frac{18.8}{\sqrt{60} } } , 131+1.96 \times {\frac{18.8}{\sqrt{60} } } ]

                                                  = [126.24 , 135.76]

Therefore, 95% confidence interval for the population mean is [126.24 , 135.76].

Now, with​ 90% confidence, it can be said that the population mean price lies in the first interval. With​ 95% confidence, it can be said that the population mean price lies in the second interval. The ​95% confidence interval is wider than the​ 90%.

7 0
3 years ago
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