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ale4655 [162]
3 years ago
9

There is a book sale at the libaray the price for each book is $4 which expression can be used to show how much money the librar

y will make if it sells 289 books? Use the number on the tiles to complete your answer.
Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
4 x 289= the total cost
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Find an equation of the line that passes through the point (4, 3) and is perpendicular to the line 2x + 9y − 6 = 0.
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Perpendicular has the reciprocal slope and u have to put the point given into point slope.

y-3=9/2(x-4)

(The slope of the original equation was -2/9)
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To shift the graph of an equation some number of units to the
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Prove that u(n) is a group under the operation of multiplication modulo n.
katrin2010 [14]

Answer:

The answer is the proof so it is long.

The question doesn't define u(n), but it's not hard to guess.


Group G with operation ∘

For all a and b and c in G:

1) identity: e ∈ G, e∘a = a∘e = a,

2) inverse: a' ∈ G, a∘a' = a'∘a = e,

3) closed: a∘b ∈ G,

4) associative: (a∘b)∘c = a∘(b∘c),

5) (optional) commutative: a∘b = b∘a.


Define group u(n) for n prime is the set of integers 0 < i < n with operation multiplication modulo n.


If n isn't prime, we exclude from the group all integers which share factors with n.


Identity: e = 1. Clearly 1∘a = a∘1 = a. (a is already < n).


Closed: u(n) is closed for n prime. We must show that for all a, b ∈ u(n), the integer product ab is not divisible by n, so that ab ≢ 0 (mod n). Since n is prime, ab ≠ n. Since a < n, b < n, no factors of ab can equal prime n. (If n isn't prime, we already excluded from u(n) all integers sharing factors with n).


Inverse: for all a ∈ u(n), there is a' ∈ u(n) with a∘a' = 1. To find a', we apply Euclid's algorithm and write 1 as a linear combination of n and a. The coefficient of a is a' < n.


Associative and Commutative:

(a∘b)∘c = a∘(b∘c) because (ab)c = a(bc)

a∘b = b∘a because ab = ba.


5 0
2 years ago
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Changing Bases to Evaluate Logarithms In Exercise, use the change-of-base formula and a calculator to evaluate the logarithm.
Ymorist [56]

Answer:

\frac{3}{2}

Step-by-step explanation:

Changing Bases to Evaluate Logarithms

log_{16}(64)

Apply change of base formula'

log_b(a)= \frac{log a}{log b}

log term should be the numerator and denominator is the log base

log_{16}(64)

log_{16}(a)= \frac{log 64}{log 16}

64 is 4^3  and 16 is 4^2

log_{16}(a)= \frac{log 4^3}{log 4^2}

Move the exponent before log

\frac{3log 4}{2log 4}

top and bottom has same log so cancel it out

\frac{3}{2}

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3 years ago
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