Answer:
To convert hexadecimal number 11BA to decimal, follow these two steps:
Start from one's place in 11BA : multiply ones place with 16^0, tens place with 16^1, hundreds place with 16^2 and so on from right to left
Add all the product we got from step 1 to get the decimal equivalent of 11BA.
Using the above steps, here is the work involved in the solution for converting 11BA to decimal number (Don't forget that we start from ones place to so on...)
Decimal equivalent of "A" = (A) 10 × 16^0 = 10
Decimal equivalent of "B" = (B) 11 × 16^1 = 176
Decimal equivalent of "1" = 1 × 16^2 = 256
Decimal equivalent of "1" = 1 × 16^3 = 4096
Decimal equivalent of "11BA" = 409625617610
11BA = 4538
Here is the final answer, The hexadecimal number 11BA converted to decimal is therefore equal to:
4538
You should change the name of the function
Answer:
5) 3 0 0
Explanation:
Given data
int [] val = { 3, 10, 44 };
The total number of parameters of given array are 3, so total length of array is also 3.
The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}
The value of array at index 0 is = 3
similarly
value at index 1 = 10
value at index 2 = 44
Here, Int i = 1 is storing the value '1' in integer variable i.
In addition to that, any value of index 'i' of an array is selected using array[i].
Therefore,
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '1' of the array because i = 1.
So value at index 1 would be = val[1] = 0
The term i++ is incrementing the value of i, it makes i =2
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '2' of the array because i = 2 now.
So value at index 2 would be = val[2] = 0
Hence, the output would be {3 0 0}. So 5th option is correct.
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Answer:
Correct answer is option (2) that is "return".
Explanation:
In any programming language, a variable name can be made up of letters (lower and upper case) and digits. we can also use "_" underscore character for declaring the variables but we cannot use any special character like “$”.We cannot use digits in the beginning of variables name. And we also cannot use reserved keywords of the language like "new","return","while" etc. There should not be space between the variable names. Options 1, 3 and 4 are not violating any of these properties. But in option (2), "return" is a reserved keyword. That is why it is not a valid variable name.
Some example of valid variables name:
foo
BAZ
Bar
_foo42
foo_bar
Some example of invalid variables name:
$foo ($ not allowed)
while ( keywords )
2foo (started with digit)
my foo (spaces )
