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Sonbull [250]
4 years ago
11

36°+36°+36°+36°+36°+36°+36°= PLS HELP

Mathematics
2 answers:
olasank [31]4 years ago
8 0

Answer:

252°

Step-by-step explanation:

36°+36°+36°+36°+36° \\ +36°+36°=252°

Alecsey [184]4 years ago
8 0

Answer:

252 degrees

Step-by-step explanation:

36*7 is the same as 36+36+36+36+36+36+36

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What number is being distributed in the following problem: -(6x -2)
kotegsom [21]

Answer:

2

Step-by-step explanation:

ya

6 0
3 years ago
Please help me with this
kherson [118]

Answer:

A

Step-by-step explanation:

The interception of the two lines is the solution point.

6 0
3 years ago
The average of five numbers is 790.6. If the first four numbers are 80.2, 91.6,123,and 204.7,what is the sum of the five numbers
aleksklad [387]

Answer:

291 .1

Step-by-step explanation:

80.2 + 91.6 + 123 + 204.7 + x = 790.6

790.6 - 499.5 = 291. 1

8 0
3 years ago
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
3 years ago
Consider the expression. What is the result of applying the quotient of powers rule to the expression?
fenix001 [56]

Answer:

Let us consider the expression:

\frac{a^5\cdot b^6}{a^2\cdot b^9}     (1)

Now, the quotient of power rules says that the numbers that have same base can be find by subtracting if powers are with same sign

And adding if powers are with opposite sign.

We will solve equation (1) by this quotient of power rule.

So, it can be rewritten as:

a^{5-2}\cdot b^{6-9}

\Rightarrow a^{3}\cdot b^{-3}.

 

8 0
4 years ago
Read 2 more answers
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