Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
angle bisector
Step-by-step explanation:
True - since the outlier is way off it will cause your average to mess up which is why we test multiple times to make sure we are more accurate with our numbers
Answer:
I think the answer is repeating because it'd be
0.55
1-1/6*3/2
multiply the two fractions
1/6*3/2
Cross out 3 and 6, divide by 3.
1/2 * 1/2
multiply the numerators together
1*1=1
multiply the denominators together
2*2=4
1-1/4
pretend that 1 has a denominator which is 1
1/1-1/4
find the common denominator for 1/1 which is 4
multiply by 4 for 1/1
1*4/1*4=4/4
4/4-1/4
Answer:
3/4