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2 years ago

What is the relationship between the two ratios?

Mathematics

2 answers:

aev [14]2 years ago

6 0

Well take the two ratios and simplify down.
(10) (5)(2) (5)
----- = ------- = -----
(14) (7)(2) (7)

(30) (5)(6) (5)
----- = -------- = -----
(36) (6)(6) (6)

So we simplified both fractions down to:
(5) (5)
----- ------
(7) (6)

Since we know (5/7) and (5/6) are not equal, we know that they are not proportional.

antoniya [11.8K]2 years ago

4 0

10/14 = 5/7
30/36 = 5/6

answer
not proportional

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Complete the table of inputs for the given function.

Alecsey [184]

Answer:

a. $x = \frac{3}{8}$

b. $g(0) = 3$

c. $x = 1$

d. $g(3) = -21$

Step-by-step explanation:

Given

$g(x) = 3 - 8x$

Solving (a): When g(x) = 0

Substitute 0 for g(x)

$g(x) = 3 - 8x$

$0 = 3 - 8x$

Solve for 8x

$8x = 3$

Solve for x

$x = \frac{3}{8}$

Solving (b): when x = 0

Substitute 0 for x

$g(x) = 3 - 8x$

$g(0) = 3 - 8 * 0$

$g(0) = 3 - 0$

$g(0) = 3$

Solving (c): When g(x) = -5

Substitute -5 for g(x)

$g(x) = 3 - 8x$

$-5 = 3 - 8x$

Solve for 8x

$8x = 3 + 5$

$8x = 8$

Solve for x

$x = \frac{8}{8}$

$x = 1$

Solving (d): When x = 3

Substitute 3 for x

$g(x) = 3 - 8x$

$g(3) = 3 - 8 * 3$

$g(3) = 3 - 24$

$g(3) = -21$

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3 years ago

What is 78 in scientific notation

4vir4ik [10]

Well first you take 78 and turn it to 7.8
then multiply by 10000
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3 0

3 years ago

If i throw one die, probability to i get 2 is

Whitepunk [10]

Throw two die you will get two

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2 years ago

Read 2 more answers

A study of 4,430 U.S. adults found that 2,913 were obese or overweight. The 95% confidence interval for the proportion of adults

IrinaK [193]

Answer:

$0.658 - 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.644$

$0.658 + 1.96\sqrt{\frac{0.658(1-0.658)}{4430}}=0.672$

We are 95% confident that the true proportion of adults overweight is between 0.644 and 0.672

Step-by-step explanation:

We can begin founding the estimated proportion of people overweight:

$\hat p =\frac{2913}{4430}= 0.658$

We need to find a critical value for the confidence level using the normal standard distribution. We know that 95% is the confidence level, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: