Answer:
-10x^2-33x+1
Step-by-step explanation:
=>6x(x-4)-16x^2-(9x-1)
multiply 6x with (x-4) and multiply - with (9x-1).
= 6x^2-24x-16x^2-9x+1
arrange the like terms with same powers of x with the respective sign.
= 6x^2-16x^2-24x-9x+1
simplify by using the respective arthematic operations.
= -10x^2-33x+1
The value has decreased because the amount he gets in Canadian dollars has decreased for the exact same amount he has in yuan.
I.e. Before: 12000/6.64 = 1807.23 Canadian dollars
Present: 12000/6.78 = 1769.91 Canadian dollars
Answer: Yes, they are equal
lets see how,
solve the given equation,
–3(0.15 – 0.2 + 0.25p)
Step 1: Inside the bracket solve the similar variables i.e. (0.15 - 0.2)
So it will become,
= -3 ( -0.05 + 0.25p )
Step 2: Multiply each term in the bracket by -3
So it will be,
((-3*-0.05 ) + (-3 * 0.25p))
= 0.15 - 0.75p
Hence 0.15 – 0.75p is equal to –3(0.15 – 0.2 + 0.25p )
Answer:
3¼
Step-by-step explanation:

We take any of the two points shown in the question. I will take (-3, 1) and (1, 14).
x¹ = -3
y¹ = 1
x² = 1
y² = 14
Now, we sub these figures into the formula.

This leaves us with 14-1/1+3, which we can make into 13/4
13/4 = 3¼
<em>Disclaimer</em><em>:</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>actually</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>two</em><em>,</em><em> </em><em>but</em><em> </em><em>a</em><em> </em><em>way</em><em> </em><em>to</em><em> </em><em>distinguish</em><em> </em><em>one</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>other</em><em>.</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>label</em><em> </em><em>of</em><em> </em><em>sorts</em><em>.</em>
1,342÷33 estimate 1,300÷30 now lets check our answer so its 43.3333333333 if you don't think im sure check it on the calculator