First, let us restate the given conditions
c is 5 more than variable a ( c = a + 5)
c is also three less than variable a (c = a - 3)
Now, lets look at the answer choices and or given
c = a − 5
c = a + 3
Here, c is 5 less than "a"...so automatically disqualified
a = c + 5
a = 3c − 3
Here, we have to get "C" by itself in both top and bottom equation.
So,
Simplified version :
c = a - 5
Here, c is 5 less than "a"...so automatically disqualified
a = c − 5
a = 3c + 3
Here also, we have to get "C" by itself in both top and bottom equation.
So,
simplified version:
c = a + 5
Here, c is 5 more than "a"...so we continue
c = (a - 3) / 3
Here, c is 3 less than "a" <u>divided by 3</u><u /> . So, this is not correct
c = a + 5
c = a − 3
Here, c is 5 more than "A"
Also, c is 3 less than "a"
Which satisfies the given.
So, our answer is going to be the last one:
c = a + 5
c = a - 3
Answer:
-2w-20
Step-by-step explanation:
distribute => 4w-20-6w = -2w-20
9b - 12b² factorised would be 3b(3 - 4b).
You can find this as you must first find a common factor between 9b and -12b², which would be 3b. We can then take this out of the bracket and divide both terms by 3b to get the final answer, which leaves us with 3b(3 - 4b).
I hope this helps!
Answer:
obtuse
Step-by-step explanation:
The largest angle is more than 90°, so the triangle is called an "obtuse" triangle.
Here are the classifications based on the measure of the largest angle:
< 90° -- acute triangle
= 90° -- right triangle
> 90° -- obtuse triangle . . . . . like the one in this problem statement
