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Mamont248 [21]
3 years ago
13

How to find the missing side of a 45 45 90 triangle?

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0
Hope you wanted that.

Hope it helps!
#MissionExam001

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The altlas v rocket could go 1 full mile in just 1/10 of a second. How fast did it travel?
Yanka [14]

Answer:

10 miles per second

Step-by-step explanation:

The computation of the fastage did it travel is shown below:

As per the question, it is mentioned that

1 full mile for just 1 by 10 of a second

Based on the above information

If 1 by 10 seconds is equivalent to one mile,

So, 10 by 10 (1) second would be equivalent to 10 miles per second.

hence, it could be fast by 10 miles per second

4 0
4 years ago
Help needed asap deadline is approaching
antiseptic1488 [7]
Your answer will be f(x) = 5 because, if we look at the table, no matter what x value we plug into the function, we will always get 5.
8 0
3 years ago
Solve
madam [21]

Answer:

Step-by-step explanation:

7 0
3 years ago
Cos²(90° -X).tan(180°-X).cos(180°+X)/sin(180°-X)
Naya [18.7K]

Recall some identities:

tan(x) = sin(x) / cos(x)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

sin(x - y) = sin(x) cos(y) - cos(x) sin(y)

This means we have

• cos²(90° - x) = [cos(90°) cos(x) + sin(90°) sin(x)]²

… = sin²(x)

• tan(180° - x) = sin(180° - x) / cos(180° - x)

… = [sin(180°) cos(x) - cos(180°) sin(x)] / [cos(180°) cos(x) + sin(180°) sin(x)]

… = sin(x) / (-cos(x))

… = -tan(x)

(and we also get sin(180° - x) = sin(x))

• cos(180° + x) = cos(180°) cos(x) - sin(180°) sin(x)

… = -cos(x)

So, the given expression reduces to

sin²(x) (-tan(x)) (-cos(x)) / sin(x) = sin²(x)

since tan(x) and cos(x)/sin(x) = 1/tan(x) will cancel.

3 0
3 years ago
What are the differences between solving equations in one variable? and solving equations into variables? and what are the simil
Pachacha [2.7K]

Answer:

Multiplying or dividing both sides by a negative number changes the direction of an inequality. So we cannot multiply or divide both sides by a variable unless we know that the variable is either always positive or always negative. This is not a concern when solving equalities.

When applying a decreasing function to both sides of an inequality, the direction of the inequality changes.

Swapping both sides of an inequality also changes the direction of an inequality. Again we don't have to worry about this with equalities.

4 0
3 years ago
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