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I am Lyosha [343]
3 years ago
14

Seven times the smaller

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Given:

Seven times the smaller  of two consecutive even  integers  is the same as  -300 minus 4 times the  larger integer.

To find:

The integers .

Solution:

Let the smaller even integer be x.

So, larger even integer is x+2 because they are consecutive even  integers.

Seven times the smaller  integer = 7x

-300 minus 4 times the  larger integer = -300-4(x+2)

Now,

7x=-300-4(x+2)

7x=-300-4x-8

7x+4x=-308

11x=-308

Divide both sides by 11.

x=\dfrac{-308}{11}

x=-28

So, the smaller even integer is -28.

x+2=-28+2=-26

So, the larger even integer is -26.

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2+2-1=3
2+2=4
And 4 minus 1 equals 3
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Answer ASAP, Find the quadratic equations whose roots are ½ and -5/2​
ArbitrLikvidat [17]

Answer:

4x^2+8x-5

Step-by-step explanation:

You work backwards to get (2x-1) which gets you the root 1/2 and (2x+5) which gets you the root -5/2 after this you foil what you have so (2x-1) times (2x+5). You do 2x times 2x which gives you 4x^2 2x times 5 which gives you 10x -1 times 2x which gives -2x and lastly -1 times 5 which gives you -5 now you combine like terms and get your final answer of 4x^2+8x-5

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3 years ago
Courtney is a retail store manager and will make $40000 this year. She expects to pay 28% of her income in tax, how much money w
AlexFokin [52]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the multiplier:

28/100 = 0.28

1 - 0.28 = 0.72

Multiply the total amount by this multiplier:

40,000 x 0.72 = 28,800

She will make $28,800

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8 0
3 years ago
Read 2 more answers
Tina kept a record of the amount of rainfall at her house each month. January had 3.331 February had 3.133 March had 3.313 and A
yawa3891 [41]

Answer:

3.331 , 3.313 , 3.133 , 1.333

Step-by-step explanation:

because it just is that way

4 0
3 years ago
For what value of k does the equation 6(x + 1) + 2 = 3(k5x + 1) + 3 have no solution?
NARA [144]

Answer:

k = (6/15)

Step-by-step explanation:

The equation is:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

To have no solutions, we need to have something like:

x + 7 = x + 4

where we can remove x in both sides and end with

7 = 4

So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.

First, let's try to simplify our equation:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

6*x + 6 + 2 = 3*k*5*x + 3*1 + 3

6*x + 8 = 15*k*x + 6

if 15*k = 6, then the system clerly has no solution.

then:

k = 6/15

then we get:

6*x + 8 = (6/15)*15*x + 6

6*x + 8 = 6*x + 6

8 = 6

The system has no solutions.

8 0
2 years ago
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