What element are u?<br><br> A<br> fire<br> b<br> air<br> c<br> water<br> d<br> earth

The table below displays the purchases that Graphic DesignWorks made from

AveGali [126]

If Graphic Design Works uses LIFO and has 125 shorts left in its inventory, the value of its current stock is <u>D. $1485</u>.

<h3>What is the LIFO inventory system?</h3>

The Last-In, First-Out (LIFO) method is an inventory valuation method that assumes that the last units to arrive in inventory are sold first.

The LIFO method is allowed under US GAAP. It is the opposite of FIFO (First-in, First-Out). The FIFO method assumes that the units bought first are the first to be sold.

<h3>Data and Calculations:</h3>

Month of Number Price per Total Cost

Purchase of shorts shorts

June 40 $11 440 (40 x $11)

July 60 $12 720 (60 x $12)

August 80 $13 1,040 (80 x $13)

September 90 $14 1,260 (90 x $14)

Ending inventory 125

Using LIFO:

Value of ending inventory = $1,485 ($440 + $720 + $13 x 25)

Thus, if Graphic Design Works uses LIFO and has 125 shorts left in its inventory, the value of its current stock is <u>D. $1485</u>.

Learn more about the LIFO inventory method at brainly.com/question/6640325

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2 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$