A very strong relationship. I'll take the easiest example :the bees. They are so important for our planet. Without them, we and all living creatures on earth would be on track to dispariton. Let me explain why. At first, the bees need the nectar from flowers to make honey ( source of food ). As they pollen from flower to flower, they transport pollen on their tiny little legs and in this way, they help the plants to reproduce themselves. If, for some reason, there will be no more bees. Plants and flowers will not thrive, plants will be eaten without having contribued to the productivity of the species and they will go out. No plants, no more veggies or fruits for herbivorous and humans, no more herbivorous no more food for carnivorous, etc. Also, without plants, there will be less oxygen on our planet. Slowly the fauna and flora will die on earth and then it will be our turn. That is why relationships with plants and insects are so important. Plants produce oxygen for all of us and they are a natural and healthy source of food and insects help plants to survive and thus save the species.
Answer:
the butterfish is both a predator and prey in this food chain. it is a predator because it hunts and eats sea squirts. it is prey because it is hunted and eaten by the striped bass
Answer:
D. there is less structural carbohydrate.
Explanation:
Most bacterial cells have a cell wall located outside the plasma membrane, formed by peptideoglycan or murein, which provides protection and shape to the cell. In addition to the wall, some bacteria have a polysaccharide capsule that surrounds this structure, this capsule is a carbohydrate envelope that can allow more or less flexibility to the bacterial cell. The more structural carbohydrates the polysaccharide capsule has the less flexible the bacteria will be. Thus, we can say that if E. coli has the most flexible cell envelope, compared to the envelope of other bacteria, it is because there is less structural carbohydrate in the E. coli envelope.
<h3>Answer:</h3>
Sample-C is the hydrogen.
<h3>Solution:</h3>
Data Given:
Volume = 5 cm³
Mass of Sample-C = 0.00045 g
Reference Density = 0.00009 g/cm³
Formula Used;
Density = Mass / Volume
Density = 0.00045 g / 5 cm³
Density = 0.00009 g/cm³
