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Vinil7 [7]
3 years ago
7

Using radicals, write an equivalent expression for the expression y^{\frac{1}{5}}.

Mathematics
2 answers:
marissa [1.9K]3 years ago
8 0

Answer:



Step-by-step explanation:


Blizzard [7]3 years ago
4 0
All we want to do is use the formula...
x^{ \frac{a}{n} } =  \sqrt[n]{a^x}
In doing so we should get...
\sqrt[5]{y}
This is an equivalent expression however just the radical form of your given expression.
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A bowl contained 250 skittles. The result of 25 fruit-flavored candies pulled at random is given below. Based on this informatio
Anastaziya [24]

OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!

7 0
3 years ago
BRAINLIEST FOR CORRECT ANSWER
user100 [1]
2 times 2.5 times 1.5 times 10 equals to 75 square meters.
4 0
3 years ago
One parent is a cystic fibrosis carrier, and the other has
Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0
3 years ago
What is the value of the underlined digit 24 the 2 is underlined?
zhannawk [14.2K]

Answer:

20

Step-by-step explanation:

ones= 1

tens= 10

Hundreds= 100

The difference between ones and tens is the 0. ones=1. tens=10

<u>2</u>4

The 2 is in the beginning so its the 10's place. The 4 is the second number so its in the ones place

3 0
3 years ago
It takes Emily 9 minutes to bicycle 3/10 of the way to school. How many minutes does it
xeze [42]

Answer:30

Step-by-step explanation:

3/10x=90

Use reciprocal to multiple both sides

x=answer

6 0
3 years ago
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