Answer
Find out the how many pounds of metal are in 1,950 lb of ore .
To proof
let us assume that the pounds of metal are in 1,950 lb of ore be x .
As given
In an ore, 9.8% of its total weight is metal.
ore weight = 1,950 lb
9.8% is written in the decimal form

= 0.098
Than the equation becomes
x = 0.098 × 1950
x = 191.1 pounds
Therefore the 191.1 pounds of metal are in 1,950 lb of ore .
Hence proved
The area of a rectangle is length*width.
The length of this 3x and the width is 2x-3. This means that, to find the area, you need to multiply 3x and 2x-3.
Start by writing out this equation:
A=l*w
Then, plug in your given values:
A= 3x*2x-3 (you can also write it as A= 3*x*2*x-3)
Then, following the order of operations, you start by multiplying. This makes your equation become A = 6x^2 -3. (^2 means squared). It turns into this because 3 * 2 is 6 and x * x is x^2 and you still haven’t used the 3 yet.
After this, there is nothing more that you can do to simplify the equation. Therefore, the area is 6x^2 - 3.
I hope this helped!
That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus
<span>2.607 x 10^13 dollars per person.
Avogadro's number is approximately 6.0221409x10^23.
So divide by the 231 million people. Giving
(6.0221409 x 10^23) / (231 x 10^6) = 0.02607 x 10^17
= 2.607 x 10^15 pennies
But we want dollars, so divide by 100
2.607 x 10^15 / 100 = 2.607 x 10^13 dollars</span>
to change from degrees to radians
multiply by pi/180
136 * pi/180 = 136/180 * pi
now simplify
34/45 * pi
.755556 * pi pi=3.14159
2.373648
to the nearest hundredth
2.37 radians