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posledela
3 years ago
12

A rectangle has a length of 3.6 in. and a perimeter of 16.8 in.

Mathematics
1 answer:
Paladinen [302]3 years ago
6 0

Answer: 4.8

Step-by-step explanation:

The answer is 4.8 because

3.6 x 2 = 7.2

16.8 - 7.2 = 9.6

9.6 / 2 = 4.8

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Two numbers are in the ratio of 3 to 4. If the minor is 27, find the sum of both.
german

Answer:

Step-by-step explanation:

First we must find the missing number, for that we apply a simple rule of three:

3. 4

27 ------ x

x = 27 (4) / 3 = 36

Now we just do the sum:

27 + 36 = 63

4 0
4 years ago
Read 2 more answers
Determine if the solution set for the system of equations shown is the empty set, contains one point or is infinite. 5x+7=2y and
Luda [366]

Answer:

The correct option is option B. It has one solution, and it's x=-3

Step-by-step explanation:

We have the following system of equations:

5x+7 = 2y                        (1)

y-9x=23                            (2)

Step 1: Solve for 'y' in equation (2):

y-9x = 23

y = 9x + 23

Step 2: Substitute in equation (1):

5x + 7 = 2y

5x + 7 = 2(9x + 23)

5x + 7 = 18x + 46

Step 3: Solve for x:

7 - 46 = 18x - 5x

-39 = 13x

x= -3

So the correct option is option B. It has one solution, and it's x=-3

7 0
3 years ago
Read 2 more answers
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
PLEASE HELP ASAP!!!! What is the first quartile,Q1, of the data set?
Goshia [24]
The first quartile of the data set is 28 because it is the median of the lower set.
6 0
3 years ago
Math.<br> How do I get 37/7 for this problem?
Bezzdna [24]
Try:

37/7 - 37/7 + 1 
          -----------
                4
7 0
4 years ago
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