Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
.
To find:
The 
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
The base angles of an isosceles triangle are congruent. So,
[Base angles of an isosceles triangle]
Using the angle sum property in triangle AOB, we get
Hence, the measure of angle AOB is 120 degrees.
A kilogram %30 chocolate,
b kilogram %50 chocolate,
a+b = 100 kilogram chocolate,
48.(a+b) = 30.a + 50.b
48a + 48b = 30a + 50b
18a = 2b
b = 9a
a+b = a + 9a = 10a = 100 kg
a = 10 kg
b = 9.a = 90 kg
You should use,
10 kg %30 chocolate,
90 kg %50 chocolate
Given sides of length 300 mm or 190 mm, you can form 4 different triangles:
- equilateral with sides 190 mm
- equilateral with sides 300 mm
- isosceles with two sides 190 mm and one side 300 mm
- isosceles with two sides 300 mm and one side 190 mm
The triangle inequality requires the sum of the lengths of any two sides be not less than the length of the third side. Since 2×190 > 300, you can mix and match these side lengths any way you want. With three sides and 2 choices for each, there are only a limited number of possibilities.
In the above, we have not listed ones that are simply rotations or reflections of a congruent triangle. (A 190-190-300 triangle looks the same as a 190-300-190 triangle, for example.)
Answer:
Step-by-step explanation:
∠1 = 38 {Vertically opposite angles}
∠2 = 39 + 36 = 75
Exterior angle equals the sum of opposite interior angles.
x = ∠1 +∠2
= 38 + 75
x = 113
