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shepuryov [24]
3 years ago
11

Someone solve this equation much appreciated!

Mathematics
1 answer:
daser333 [38]3 years ago
3 0

Answer:

\frac{2A}{h} = b

Step-by-step explanation:

  • this can be done by simple manipulation .
  • in the given equation, A is the subject.
  • so, by the above statement you can understand the meaning of making something as a subject.
  • given equation: A = 1/2 bh
  • multiply both the sides by 2,

2A = bh

  • divide both the sides by h,

\frac{2A}{h} = b

so, the required form is : \frac{2A}{h} = b

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The function f(x)=x-1/x+1 is never equal to zero
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That's false.  If x=1, the function equals zero.  Further:  note that x may not equal -1, as the denominator would in that case be zero.
5 0
4 years ago
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What is the arithmetic mean of the following numbers?<br> 9, 10, 6, 5, 6
CaHeK987 [17]

Answer: 7.2

Step-by-step explanation: Mean= (sum of observations/number  of observations)

=(5+6+6+9+10)/5

=(36)/5

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6 0
3 years ago
What is 47/20 written as a<br> decimale
Lelechka [254]

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Step-by-step explanation:

8 0
3 years ago
Solve the system of linear equations <br> 3x-y=10<br> 2x+y=5
omeli [17]

Answer:

The solution for the system of linear equations 3x-y=10  and 2x+y=5 is x=3 y= -1

<u>Solution: </u>

Given that two linear equations are 3x-y = 10 and 2x + y = 5

We have to find the values of “x” and “y”

Let us consider 3x – y =10 ---- eqn 1

2x + y = 5 --- eqn 2

From eqn 1 , rearranging the terms we get

y = 3x-10  --- eqn 3

By substituting the value of “y” from eqn 3 into eqn 2 we get,

2x + 3x – 10 = 5

On solving above expression, 5x – 10 = 5

5x = 15

x = 3

Substitute the value of “x” in eqn 1 to obtain “y” value

3(3) – y = 10

9 – y = 10

y = 9-10 = -1

Hence the solution for the system of linear equations 3x-y=10  

and 2x+y=5 is x=3 and y= -1

7 0
3 years ago
I have two variables, $x$ and $y$, and I want to swap their values. (For example, if $x$ has value 5 and $y$ has value "banana",
IgorLugansk [536]

Answer:

see explanation below.

Step-by-step explanation:

I have two variables, $x$ and $y$, and I want to swap their values.

For example, if $x$ has value 5 and $y$ has value "banana", then after the swap I want $x$ to have value "banana" and $y$ to have value 5.

1. Explain why the code x = y y = x doesn't work,

2. figure out what we need to do to swap the values of $x$ and $y$.

1. the code x=y means a copy of the y-value ("banana") to x

after this step, both variables x and y will have the value "banana".

Evidently the next step y=x will recopy the copied value of "banana" in x back to y.

Net result, both variables will contain "banana", not an exchange.

2. The code that will work requires a third temporary variable, say t.

We can then do a circular copy, starting with assignment of t.

t=x   (t now contains 5)

x=y  (x now contains "banana")

y=t   (y now contains 5)

Thus the exchange is now complete.

3 0
3 years ago
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