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saw5 [17]
2 years ago
14

5C%3A%20or%20%5C%3A%20a11%20" id="TexFormula1" title=" {a}^{2} {a}^{4} {a}^{5} answer \: a40 \: or \: a11 " alt=" {a}^{2} {a}^{4} {a}^{5} answer \: a40 \: or \: a11 " align="absmiddle" class="latex-formula">

​
Mathematics
1 answer:
laila [671]2 years ago
6 0
It’s a tiny the power of 11
2+4+5 = 11
Pls mark as brainliest
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GIVING BRAINLIEST TO THE PERSON THAT CAN EXPLAIN THIS THE BEST (:
Amanda [17]

Answer:

25π-24

Step-by-step explanation:

from the figure,

radius of the circle(r)=diameter of the circle(d)/2

=10/2

=5

Area of the circle(A)=πr^2

=π5^2

=25π

Again,

base of the right angle triangle(b)=6

perpendicular of right angle triangle(p)=8

we also know,

the area of right angle triangle = 1/2*base*height

=1/2*6*8

=1/2*48

=48/2

=24

Now, Area of the shaded region=Area of circle - Area of right angle triangle (given in the figure)

Area of shaded region= 25π -24

5 0
2 years ago
The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea
zheka24 [161]

Answer:

$301 - $397

Step-by-step explanation:

Using the Empirical rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ .

From the above question,

Mean = 349 , standard deviation = 24.

Confidence interval = 95%

Using 2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ – 2σ

= 349 - 2(24)

= 349 - 48

= 301

μ + 2σ

349 + 2(24)

= 349 + 48

= 397

Therefore, according to the standard deviation rule, approximately 95% of the students spent between $301 and $397 on textbooks in a semester.

8 0
3 years ago
How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)
chubhunter [2.5K]
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
%  (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\


\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135}
\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}
8 0
3 years ago
5 1/6 minus 1 2/3 PLZ HELP NOW<br>​
Ivenika [448]
21/6 simplified 7/2 or 3 1/2
5 0
2 years ago
Read 2 more answers
What is .0067 .007 .00618 .00701 .006 arranged in largest to smallest
Sidana [21]


00701, .007, .0067, .00618, .006
Step 1 : Compare the whole numbers.Step 2 : When whole numbers are same check the decimal places.Step 3 : Convert into like decimals considering the maximum decimal number.The correct order is .00701, .007, .0067, .00618, .006
5 0
3 years ago
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