Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
<u><em>The complete question is</em></u>
Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B
The picture of the question in the attached figure
Part 1) Write the ratio equivalent to: Sin B
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the values
Part 2) Write the ratio equivalent to: Csc A
we know that
In the right triangle ABC
-----> by SOH (opposite side divided by the hypotenuse)
substitute the values
therefore
Part 3) Write the ratio equivalent to: Cot A
we know that
In the right triangle ABC
-----> by TOA (opposite side divided by the adjacent side)
substitute the values
therefore
2(10-3) distribute = 2*10 is 20 and 2*3 is 6
20-6+(5-14/2)
now 20-6 is 14
14+(5-14/2)
now 14/2 is 7
14+(5-7)
now 5-7 is -2
14+-2
is 12
the answer is 12
but if you want to you can do 12/3 to get the greatest common factor
which is 4
hope i help you :P
Answer:
x=7
Step-by-step explanation:
f(x) =g(x)
12-2=x+3
10=x+3
10-3=x
x=7
Answer:
m∠H = 10°
Step-by-step explanation:
ΔFGH is an isosceles triangle. I made a diagram, so m∠F ≅ m∠H by B.A.T(base angle theorem). This is because an isosceles triangle have to congruent sides and angles.
Diagram is attached:
-Chetan K
Answer:
13 cup i hope this help
Step-by-step explanation:
