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Volgvan
4 years ago
11

Can -5 be the base of an exponential function?

Mathematics
1 answer:
sleet_krkn [62]4 years ago
5 0
No, because negative base sometimes results in non-real or imaginary value.

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#9 was the the one I need help with anyone plz help Thank You:)
pentagon [3]
Your answers are wrong. the function f(x) is like a factory. you put in something ( a number) and it will spit you out something else (a different number depending on the function). your function, f (x)= -2x+1

you can put anything in that function. let say k.
f(x=k) = -2k+1. you just replace the x with k.
in this particular problem they way f(-2) ,f(0), f(1) and f(2).
here are the results
f(x=-2) = f(-2) = -2×(-2)+1 =5
f(x=0) = f(0) = -2×(0)+1 =1
f(x=1) = f(1) = -2×(1)+1 =-1
f(x=2) = f(2) = -2×(2)+1 =-3
3 0
3 years ago
The real numbers $x$ and $y$ are such that \begin{align*} x + y &= 4, \\ x^2 + y^2 &= 22, \\ x^4 &= y^4 - 176 \sqrt{
tamaranim1 [39]

You get everything you need from factoring the last expression:

x^4-y^4=-176\sqrt7

The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with

x^4-y^4=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)

Plug in everything you know and solve for x-y:

-176\sqrt7=(x-y)\cdot4\cdot22\implies x-y=\boxed{-2\sqrt7}

4 0
3 years ago
Read 2 more answers
Bx-6y=18 and 2x-3y=9
Sloan [31]
X - 6y=18     
2x-3y=9    |*-2

   x -6y=18
-4x+6y=-18
----------------
-3x=0, x=0

2x-3y=9
2*0-3y=9
-3y=9, y=-9/3, y= -3
4 0
4 years ago
Short on time, please help!
kvv77 [185]
56.3% hope it helped ok
3 0
3 years ago
The first step in long division is to ___. divide multiply subtract
Aleonysh [2.5K]

Answer:

divide

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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