Question

Log*subscript*(3x − 2) 4096 = 3 I got x= negative 6 is this correct??

Answer 1

Remember

$log_a(b)=c$ translates to $a^c=b$
and
$log_a(b^c)=clog_a(b)$
so


4096=16^3
$log_{3x-2}(4096)=3$
$log_{3x-2}(16^3)=3$
$3log_{3x-2}(16)=3$
divide both sides by 3
$log_{3x-2}(16)=1$
translate
$(3x-2)^1=16$
3x-2=16
add 2 to both sides
3x=18
divide both sides by 3
x=6