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Sergeu [11.5K]
3 years ago
14

Evaluate the expression 4ab, for a =2 and b = 5

Mathematics
2 answers:
yan [13]3 years ago
4 0

Answer:

40

Step-by-step explanation:

4x2=8

8x5=40

expeople1 [14]3 years ago
3 0

Answer:

40

Step-by-step explanation:

you do this 4(a*b)

ab is 10 so 4*ab=40

hint (if you see two variables without a symbol in between,  multiply)

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A sequence can be generated by using an = a(n-1) + 3, where ai = 8 and n is a whole number greater than 1. What are the first fo
Georgia [21]

Answer:

J

Step-by-step explanation:

a1=8 (as given)

a2=a1+3=8+3=11

a3=a2+3=11+3=14

a4=a3+3=14+3=17

3 0
3 years ago
If 50% of a number is 60, find 5% of that number.<br> i need it rn
zhenek [66]

Answer:

6

Step-by-step explanation:

if something has 60 as it's 50 percent, then 100 percent would be 120

now we have to find 5 percent of 120:

5/100 × 120= 6

3 0
3 years ago
Read 2 more answers
Hey PLEASE HELP DUE TODAY
nadya68 [22]
What the maning of that ?
4 0
3 years ago
What is the value of A+B+E?<br> 15<br> 17<br> -15<br> 13<br><br> Thank you in advance!
ki77a [65]

Answer:

17

Step-by-step explanation:

∫ x² e⁻³ˣ dx = -1/27 e⁻³ˣ [Ax² + Bx + E] + C

Take derivative of both sides:

x² e⁻³ˣ = d/dx {-1/27 e⁻³ˣ [Ax² + Bx + E] + C}

x² e⁻³ˣ = -1/27 d/dx {e⁻³ˣ [Ax² + Bx + E]}

-27x² e⁻³ˣ = d/dx {e⁻³ˣ [Ax² + Bx + E]}

Use product rule to evaluate the derivative:

-27x² e⁻³ˣ = {e⁻³ˣ [2Ax + B] − 3e⁻³ˣ [Ax² + Bx + E]}

-27x² e⁻³ˣ = e⁻³ˣ {2Ax + B − 3 [Ax² + Bx + E]}

-27x² e⁻³ˣ = e⁻³ˣ [2Ax + B − 3Ax² − 3Bx − 3E]

-27x² e⁻³ˣ = e⁻³ˣ [-3Ax² + (2A − 3B) x + (B − 3E)]

-27x² = -3Ax² + (2A − 3B) x + (B − 3E)

Match the coefficients:

-27 = -3A

0 = 2A − 3B

0 = B − 3E

Solve the system of equations:

A = 9

B = 6

E = 2

Therefore, A + B + E = 17.

6 0
3 years ago
The mean of a population is 74 and the standard deviation is 16. The shape of the population is unknown. Determine the probabili
bulgar [2K]

Answer:

a

 P(X  >  75)=  0.35402

b

P(72 <  X  <  75 ) = 0.2529

c

P( X  <  74.7)  = 0.74041

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu =  74

  The population standard deviation is  \sigma  =  16

 Considering question a  

    The sample size is  n  =  36  

Generally the standard error of mean is mathematically represented as

     \sigma_{x} =  \frac{\sigma  }{\sqrt{n} }

=>  \sigma_{x} =  \frac{16}{\sqrt{36} }

=>  \sigma_{x} = 2.67

Generally the probability that a  random sample of size 36 yielding a sample mean of 75 or more is mathematically represented as

     P(X  >  75) =  P( \frac{X -  \mu  }{ \sigma_{x}} >  \frac{75 -  74}{ 2.67 }  )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

   P(X  >  75) =  P(Z >  0.3745   )

From the z table  the area under the normal curve representing 0.3745 to the right is  

     P(Z >  0.3745   ) =  0.35402

=>   P(X  >  75)=  0.35402

 Considering question b  

    The sample size is  n  =  104

Generally the standard error of mean is mathematically represented as

     \sigma_{x} =  \frac{\sigma  }{\sqrt{n} }

=>  \sigma_{x} =  \frac{16}{\sqrt{104} }

=>  \sigma_{x} = 1.5689

Generally the probability that a random sample of size 104 yielding a sample mean  between 72 and 75 is mathematically represented as

      P(72 <  X  <  75 ) =  P(\frac{72 - 74 }{1.5689}  <  \frac{X -  \mu }{\sigma_{x}}  < \frac{75 - 74 }{1.5689}   )

=>   P(72 <  X  <  75 ) =  P(-1.275 < Z < 0.375   )

=>   P(72 <  X  <  75 ) =  P(Z < 0.375   ) -  P(Z <  -1.275)

From the z table  the area under the normal curve representing -1.275 to to the left is

   P(Z <  -1.275) =0.10115

=> P(72 <  X  <  75 ) = 0.35402  -  0.10115

=> P(72 <  X  <  75 ) = 0.2529

Considering question c

    The sample size is  n  =  217

Generally the standard error of mean is mathematically represented as

     \sigma_{x} =  \frac{\sigma  }{\sqrt{n} }

=>  \sigma_{x} =  \frac{16}{\sqrt{217} }

=>  \sigma_{x} = 1.086

Generally the probability that a  random sample of size 217 yielding a sample mean of less than 74.7 is mathematically represented as

       P( X  <  74.7) =  P(\frac{X -  \mu }{\sigma_x}  < \frac{ 74.7 -  74 }{ 1.086 })

=>   P( X  <  74.7) =  P(Z < 0.6446 )

From the z table  the area under the normal curve representing 0.6446  to to the left is

     P(Z < 0.6446 )  =  0.74041

=>  P( X  <  74.7)  = 0.74041

8 0
3 years ago
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